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2 years ago

What is the sum of 3/2x and 7/4x

2 answers:

8 0

3/2x + 7/4x
Dina a common denominator which is 4, so multiply 3/2 by 2 to get the bottom number to be 4.

Expressed: 6/4x+7/4x
Now add them: 11/4x

Advocard [28]2 years ago

4 0

3/2x +7/4x = ...........

3/2x(4/4)+7/4x(2/2)

12/8x+14/8x = 26/8x

26/8x = 13/4x(3.25x)

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Factorise 15x+25<br><br>thank you for any help

scoray [572]

Answer: 5(3x+5)

Step-by-step explanation:

To factor this expression we need to pull out the greatest common factor of the 2 numbers, 15 and 25. This factor is 5.

Now divide both numbers by 5 and put a 5 on the outside of the new expression to look like: $5(3x+5)$ and this is as far as it can be factored.

4 0

2 years ago

Read 2 more answers

7. If W = 3Z, and Z is 30% of R, then W is what

dem82 [27]

Answer:

90%

Step-by-step explanation:

Let R = 100

Since, Z = 30% of R

Therefore, Z = 30% *100 = 30

Since, W = 3Z

Therefore, W = 3*30 = 90

Percentage of W of R

$= \frac{Value \: of \: W}{Value \: of \: R} \times 100\\\\=\frac{90}{100} \times 100\\\\Percentage \:of \:W \:of \:R =90\%$

7 0

2 years ago

A specimen of aluminum having a rectangular cross section 10 mm 12.7 mm (0.4 in. 0.5 in.) is pulled in tension with 35,500 N (80

miskamm [114]

Answer:

$\epsilon = 3.958\times 10^{-3}$

Step-by-step explanation:

The Young's Module of Aluminium is $E = 69\times 10^{9}\,Pa$ . The axial stress on the specimen is:

$\sigma = \frac{F}{A_{t}}$

$\sigma = \frac{35500\,N}{(0.01\,m)\cdot (0.013\,m)}$

$\sigma = 2.731\times 10^{8}\,Pa$

The strain is derived of following expression:

$\epsilon = \frac{\sigma}{E}$

$\epsilon = \frac{2.731\times 10^{8}\,Pa}{69\times 10^{9}\,Pa}$

$\epsilon = 3.958\times 10^{-3}$

4 0

2 years ago

It takes for three gardeners 90 minutes to weed a garden. If the job is to be done in only 15 minutes, how many more gardeners n

andrezito [222]

3 gardeners :90 minutes
? Gardeners : 15 minutes
1 gardener : 270 minutes
? Gardeners : 270/15
18 gardeners

6 0

2 years ago

Read 2 more answers

The national average for mathematics SATs in 2011 was 514 and the standard deviation was approximately 40. a) Within what bounda

blondinia [14]

Answer:

$0.75 = 1-\frac{1}{k^2}$

If we solve for k we can do this:

$\frac{1}{k^2}= 1-0.75=0.25$

$\frac{1}{0.25}= k^2$

$k^2 =4$

$k =\pm 2$

So then we have at last 75% of the data withitn two deviations from the mean so the limits are:

$Lower = \mu -2\sigma = 514- 2*40=434$

$Upper = \mu +2\sigma = 514 + 2*40=594$

Step-by-step explanation:

We don't know the distribution for the scores. But we know the following properties:

$\mu = 514 , \sigma =40$

For this case we can use the Chebysev theorem who states that "At least $1 -\frac{1}{k^2}$ of the values lies between $\mu -k\sigma$ and $\mu +k\sigma$ "

And we need the boundaries on which we expect at least 75% of the scores. If we use the Chebysev rule we have this:

$0.75 = 1-\frac{1}{k^2}$

If we solve for k we can do this:

$\frac{1}{k^2}= 1-0.75=0.25$

$\frac{1}{0.25}= k^2$

$k^2 =4$

$k =\pm 2$

So then we have at last 75% of the data withitn two deviations from the mean so the limits are:

$Lower = \mu -2\sigma = 514- 2*40=434$

$Upper = \mu +2\sigma = 514 + 2*40=594$

4 0

2 years ago