Answer:
a) P(identified as containing explosives)=P(actually contains explosives and identified as containing explosives)+P(actually not contains explosives and identified as containing explosives)
=(10/(4*106))*0.95+(1-10/(4*106))*0.005 =0.005002363
hence probability that it actually contains explosives given identified as containing explosives)
=(10/(4*106))*0.95/0.005002363=0.000475
b)
let probability of correctly identifying a bag without explosives be a
hence a =0.99999763 ~ 99.999763%
c)
No as even if that becomes 1 ; proportion of true explosives will always be less than half of total explosives detected,
As the key suggests, the left part is the integer part of the number, while the digit on the right is the decimal part of the number.
So, for example, the first row describes the two values 97.2 and 97.8, while the second row describes the values 98.1, 98.3 (repeated twice), 98.5, 98.6 and 98.7 (repeater three times).
So, the number of values is given by the number of leaves: you simply have to count how many digits are there on the right part of the screen.
The answer is thus 24
The correct answer to your question is false. this is because congruent triangles must have the same 3 angles and the same 3 sides, and while these triangles have the same angles, they dont have the same sides.
let me know if you have any other questions
:)
Answer:
b
Step-by-step explanation:
Answer:
Jamal received 2,880 votes
Step-by-step explanation:
In the election,
Jamal received 40% of all votes
Tran received 100% - 40% = 60% that is 4,320 votes
Let x be the number of votes Jamal received. Then
x - 40%
4,320 - 60%
Write a proportion:
