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Wewaii [24]
1 year ago
15

Lyle graphs triangle ABC on coordinate axes. He performs two transformations on this figure that result in the congruent triangl

e XYZ Which series of transformations did Lyle most likely use?
a translation left and then a dilation with a scale factor of 3
a dilation with a scale factor of 2.5 and then a rotation 180' counterclockwise
a rotation 90' clockwise and then a reflection across the y-axis
a reflection across the x-axis and then a dilation with a scale factor of 0.25
C​
Mathematics
1 answer:
Shtirlitz [24]1 year ago
3 0

Answer:

a rotation 90˚ clockwise and then a reflection across the y-axis

Step-by-step explanation:

I'm doing the test right now

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Suppose that you were going to using the Permutation approach to see if there was a difference in the amount of money spent on c
galina1969 [7]

Answer:

Assuming null hypothesis - that there is no difference in the cell phone bills between out of state and in state.

Step-by-step explanation:

3 0
2 years ago
An urn contains six chips, numbered 1 through 6. two are chosen at random and their numbers are added together. what is the prob
vitfil [10]
<span>2/15 if drawn without replacement. 1/9 if drawn with replacement. Assuming that the chips are drawn without replacement, there are 6 * 5 different possibilities. And that's a low enough number to exhaustively enumerate them. So they are: 1,2 : 1,3 : 1,4 : 1,5 : 1,6 2,1 : 2,3 : 2,4 : 2,5 : 2,6 3,1 : 3,2 : 3.4 : 3,5 : 3,6 4,1 : 4,2 : 4.3 : 4,5 : 4,6 5,1 : 5,2 : 5.3 : 5,4 : 5,6 6,1 : 6,2 : 6.3 : 6,4 : 6,5 Of the above 30 possible draws, there are 4 that add up to 5. So the probability is 4/30 = 2/15 If the draw is done with replacement, then there are 36 possible draws. Once again, small enough to exhaustively list, they are: 1,1 : 1,2 : 1,3 : 1,4 : 1,5 : 1,6 2,1 : 2,2 : 2,3 : 2,4 : 2,5 : 2,6 3,1 : 3,2 : 3,3 : 3.4 : 3,5 : 3,6 4,1 : 4,2 : 4.3 : 4,4 : 4,5 : 4,6 5,1 : 5,2 : 5.3 : 5,4 : 5,5 : 5,6 6,1 : 6,2 : 6.3 : 6,4 : 6,5 : 6,6 And of the above 36 possibilities, exactly 4 add up to 5. So you have 4/36 = 1/9</span>
7 0
2 years ago
Repeated student samples. Of all freshman at a large college, 16% made the dean’s list in the current year. As part of a class p
Dima020 [189]

Answer:

a) p-hat (sampling distribution of sample proportions)

b) Symmetric

c) σ=0.058

d) Standard error

e) If we increase the sample size from 40 to 90 students, the standard error becomes two thirds of the previous standard error (se=0.667).

Step-by-step explanation:

a) This distribution is called the <em>sampling distribution of sample proportions</em> <em>(p-hat)</em>.

b) The shape of this distribution is expected to somewhat normal, symmetrical and centered around 16%.

This happens because the expected sample proportion is 0.16. Some samples will have a proportion over 0.16 and others below, but the most of them will be around the population mean. In other words, the sample proportions is a non-biased estimator of the population proportion.

c) The variability of this distribution, represented by the standard error, is:

\sigma=\sqrt{p(1-p)/n}=\sqrt{0.16*0.84/40}=0.058

d) The formal name is Standard error.

e) If we divided the variability of the distribution with sample size n=90 to the variability of the distribution with sample size n=40, we have:

\frac{\sigma_{90}}{\sigma_{40}}=\frac{\sqrt{p(1-p)/n_{90}} }{\sqrt{p(1-p)/n_{40}}}}= \sqrt{\frac{1/n_{90}}{1/n_{40}}}=\sqrt{\frac{1/90}{1/40}}=\sqrt{0.444}= 0.667

If we increase the sample size from 40 to 90 students, the standard error becomes two thirds of the previous standard error (se=0.667).

0 0
2 years ago
100/225 square feet of your bakery will be used as your storefront, where customers come visit. The rest kill be used for storag
Lelu [443]
The answer is 5/9. I showed a bit more work on the other post
7 0
1 year ago
Find the size of each of two samples (assume that they are of equal size) needed to estimate the difference between the proporti
lesya [120]

Answer:

a) the sample size (n) = 156.25≅ 156

Step-by-step explanation:

<u>Step1 </u>:-

Given the two sample sizes are equal so n_{1} =n_{2} = n

Given the standard error (S.E) = 0.04

The standard error of the proportion of the given  sample size

S.E = \sqrt{\frac{pq}{n} }

Step 2:-

here we assume that the proportion of boys and girls are equally likely

p= 1/2 and q= 1/2

S.E = \sqrt{\frac{p(1-p)}{n} } \leq \frac{\frac{1}{2} }{\sqrt{n} }

\sqrt{n} = \frac{\frac{1}{2} }{S.E}

squaring on both sides, we get

n = \frac{1}{(2X0.04)^{2} }

on simplification, we get

n= 156.25 ≅ 156

sample size (n) = 156

<u>verification</u>:-

S.E = \sqrt{\frac{pq}{n} }= \sqrt{\frac{1}{4X156} } =\sqrt{0.0016}  

Standard error = 0.04

4 0
1 year ago
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