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maw [93]
2 years ago
15

The average age three people running for election is 42. A fourth person joins the race and the average drops to 40. What is the

fourth person's age?
Mathematics
1 answer:
bogdanovich [222]2 years ago
5 0

Let a_1,\ldots,a_4 denote the ages of the 4 candidates. Then

\dfrac{a_1+a_2+a_3+a_4}4=40

a_1+a_2+a_3+a_4=160

\dfrac{a_1+a_2+a_3}3+\dfrac{a_4}3=\dfrac{160}3

The average age of the first 3 candidates is 42, so

\dfrac{a_4}3=\dfrac{160}3-42

\implies\boxed{a_4=160-3\cdot42=34}

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Nutka1998 [239]

Answer:

$62.60

Step-by-step explanation:

C(190) = 22 + 0.1*190 = 22 + 19 = $41

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8 0
2 years ago
Read 2 more answers
Which function has the domain x>or= -11
iogann1982 [59]
I'm assuming this is multiple choice and you forgot to post the answers. I'll take a guess and say it probably looks something like this:
y = \sqrt{x + 11}
Because you can't take the square root of a negative number without getting an imaginary result, resulting in the function having a closed domain limit.
6 0
2 years ago
1600 dollars is placed in an account with an annual interest rate of 5.25%. How much will be in the account after 25 years, to t
Andru [333]

Step-by-step explanation:

Exponential Functions:

y=ab^x

y=ab

x

a=\text{starting value = }1600

a=starting value = 1600

r=\text{rate = }5.25\% = 0.0525

r=rate = 5.25%=0.0525

\text{Exponential Growth:}

Exponential Growth:

b=1+r=1+0.0525=1.0525

b=1+r=1+0.0525=1.0525

\text{Write Exponential Function:}

Write Exponential Function:

y=1600(1.0525)^x

y=1600(1.0525)

x

Put it all together

\text{Plug in time for x:}

Plug in time for x:

y=1600(1.0525)^{25}

y=1600(1.0525)

25

y= 5750.0628984

y=5750.0628984

Evaluate

y\approx 5750.06

y≈5750.06

3 0
2 years ago
A new car is purchased for 17900 dollars. The value of the car depreciates at 13% per year. What will the value of the car be, t
Hatshy [7]
17,900 * (1 -0.13)^7 = 6752.86 . . . . dollars
7 0
2 years ago
After drawing the line y = 2x − 1 and marking the point A = (−2, 7), Kendall is trying to decide which point on the line is clos
igor_vitrenko [27]

Answer:

Step-by-step explanation:

Having drawn the line, Kendall must verify that the point P belongs to the line y = 2x-1 and then calculate the distance between A-P  and verify if it is the closest to A or there is another one of the line

Having the point P(3,5) substitue x to verify y

y=2*(3)-1=6-1=5 (3,5)

Now if the angle formed by A and P is 90º it means that it is the closest point, otherwise that point must be found

d_{AP}=\sqrt{(y_{2}-y_{1})^{2}+(x_{2}-x_{1})^{2}}=\sqrt{(5-7)^{2}+(3-(-2}))^{2}}=\\\sqrt{(-2)^{2}+(5)^{2}}=\sqrt{29}

and we found the distance PQ and QA

; d_{PQ}=\sqrt{125}, d_{QA}=12

be the APQ triangle we must find <APQ through the cosine law (graph 2).

3 0
2 years ago
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