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2 years ago

If BE−→− bisects ∠ABD and m∠ABD = 66°, find m∠ABE

Mathematics

1 answer:

Monica [59]2 years ago

4 0

Answer:

m∠ABD = 132 °

Step-by-step explanation:

m∠ABE = m∠DBE

and

m∠ABD = m∠ABE + m∠DBE

Because m∠ABE = 66°, therefore m∠DBE = 66°, so that

m∠ABD = 66° + 66° = 132°

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densk [106]

Answer:

The probability of getting a sample with 80% satisfied customers or less is 0.0125.

Step-by-step explanation:

We are given that the results of 1000 simulations, each simulating a sample of 80 customers, assuming there are 90 percent satisfied customers.

Let $\hat p$ = sample proportion of satisfied customers

The z-score probability distribution for the sample proportion is given by;

Z = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, p = population proportion of satisfied customers = 90%

n = sample of customers = 80

Now, the probability of getting a sample with 80% satisfied customers or less is given by = P( $\hat p \leq$ 80%)

P( $\hat p \leq$ 80%) = P( $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ $\leq$ $\frac{0.80-0.90}{\sqrt{\frac{0.80(1-0.80)}{80} } }$ ) = P(Z $\leq$ -2.24) = 1 - P(Z < 2.24)

= 1 - 0.9875 = 0.0125

The above probability is calculated by looking at the value of x = 2.24 in the z table which has an area of 0.9875.

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2 years ago

The Hazell family has 4 children. Murphy is 1 year younger than his older brother Michael. Keira is 2 years younger than Murphy.

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Isabelle is 7 years old

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2 years ago

Bill has an algorithm, find2D, to find an element x in an n × n array A. The algorithm find2D iterates over the rows of A and ca

KatRina [158]

Answer:

The worst case run time of Find2D is O(n²) because the worst case run time of arrayFind is O(n) and this function will be called for n rows from Find2D algorithm, hence O(n²) .

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Step-by-step explanation:

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2 years ago

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Step-by-step explanation:

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2 years ago

Sia sells large candles for $3 each and small candles for $2 each. She sold 17 candles for $46.00. How many of each size candle

kipiarov [429]

Answer:

The number of large size candles sells are 12 and the number of small size candles are 5 .

Step-by-step explanation:

As given

Sia sells large candles for $3 each and small candles for $2 each.

She sold 17 candles for $46.00.

Let us assume that the large size candle sells are x .

Let us assume that the small size candle sells are y.

Equation becomes

x + y = 17

3x + 2y = 46

Multiply x + y = 17 by 3 and subtracted from 3x + 2y = 46 .

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Put in the equation x + y = 17 .

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