Answer:
- Time = approximately mid 2012
- Oil import rate = 3600 barrels
Step-by-step explanation:
<h3><em>Unclear part of the question</em></h3>
- I(t) = −35t² + 800t − 1,000 thousand barrels per day (9 ≤ t ≤ 13)
- According to the model, approximately when were oil imports to the country greatest? t = ?
<h3>Solution</h3>
Given the quadratic function
- <em>The vertex of a quadratic function is found by a formula: x = -b/2a</em>
<u>As per given function:</u>
<u>Then</u>
- t = - 800/2*(-35) = 11.43 which is within given range of 9 ≤ t ≤ 13
This time is approximately mid 2012.
<u>Considering this in the function, to get oil import rate for the same time:</u>
- l(11.43) = -35*(11.43)² + 800*11.43 - 1000 = 3571.4285
<u>Rounded to two significant figures, the greatest oil import rate was</u>:
Answer:
Kadeem takes 10 minutes longer to drive 25 miles.
Step-by-step explanation:
50m/hr = 25m/ half an hour
75m/hr = 25m/20 minutes
Answer:
- <u><em>Option b. just below 30%</em></u>
<u><em></em></u>
Explanation:
Please, see attached the <em>histogram that represents the distribution of acceptance rates (percent accepted) among 25 business schools in 2004. </em>
<em />
The<em> median</em> is the value that separates the lower 50% from the upper 50% of the data.
Since there are 25 business schools, the middle value is the number 13.
The height of each bar is the<em> frequency</em> or number of business school for that acceptace rate:
- The first bar has frequency of 1 school
- The second bar has frequency of 3 schools: cummulative frequency: 1+3=4.
- The third bar has frequency 5 schools: cummulative frequency 4 + 5 = 9.
- The fourth bar has frequency 3 schools: cummulative frequency: 9+3=12.
Then, the 13th value is on the next bar, the fifth bar.
The fifth bar has acceptance rates 25 ≤ rate < 30.
That means that the median acceptance rate is greater than or equal to 25 and less than 30.
Thus, the choice is the option <em>b. just below 30%.</em>
25320+11310=36,630 or 12,430+24,200=36,630
The answer that I got is C=-6