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irga5000 [103]
2 years ago
13

Nancy Gerald, production control manager at The Open-Pit Furnace Co., has a total of $497.25 deducted from her monthly paycheck

for Social Security and Medicare taxes. What is her monthly salary?
Mathematics
1 answer:
Romashka [77]2 years ago
5 0

Missing portion in question:

Tax rate for Social Security and Medicare for the company The Open-Pit Furnace Co. is not given in the question. Usually these taxes apply on following rate:

Social Security Tax Rate = 6.2%

Medicare Tax Rate = 1.45%

Answer:

$6,500

Step-by-step explanation:

Total deducted amount from her salary was $497.25 i.e. some of the taxes for social security and medicare. If these taxes are on the rate mentioned above, total salary can be calculated.

Total deduction = (6.2%+1.45%) of the salary

497.25=7.65% of the salary

Let the total salary = $x

497.25=\frac{7.65}{100}*x\\=\frac{497.25*100}{7.65} \\=\frac{49725}{7.65} \\=6500

So, her monthly salary is $6500

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Answer:

  4 hours

Step-by-step explanation:

This equation represents the data:

  2.5(12.75x + 24.50) = 188.75

  31.875x +61.25 = 188.75 . . . . . eliminate parentheses

  31.875x = 127.50 . . . . . . . . subtract 61.25

  x = 4 . . . . . . . . . . . . . . . . . . . divide by 31.875

Big Time Movers worked 4 hours on New Year's Day.

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A theater has tickets at $6 for adults, $3.50 for students, and $2.50 for children under 12 years old. a total of 278 tickets we
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2 years ago
For a set of data: x = (0,1,2,3,4,5,6) and y=(36, 28, 25, 24, 23, 21, 19), is it wise to use a linear regression to extrapolate
melisa1 [442]

Answer:

The problem with this solution is that a regression model is not recommended to extrapolate because we do not know if the linear relation that we calculated for a specific range of x values still holds outside this range.

Step-by-step explanation:

We have a linear regression model, with a range of the independent variable "x" that goes from 0 to 6.

The regression model finds a good fit (r=0.8582).

As it has a good fit, it is proposed to use this model to extrapolate and calculate the value of y for x=50.

It is not recommended to extrapolate a regression model unless we are really sure that the model is still valid within the range within we are extrapolating.

This means that if we have no proof that y has a linear relation in a range of x that includes x, the extrapolation has no validity and can lead to serious errors.

A linear regression model is only suitable for interpolation or extrapolating within the range we are sure that the relation between y and x is linear within a certain acceptable error.

4 0
1 year ago
A brewery produces cans of beer that are supposed to contain exactly 12 ounces. But owing to the inevitable variation in the fil
MArishka [77]

Answer:

T \sim N (\mu = 6*12=72 , \sigma= \sqrt{6} *0.3=0.735)

P(T \leq 72) = P(Z< \frac{72-72}{0.735}) = P(Z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solutio to the problem

Let X the random variable that represent the amount of beer in each can of a population, and for this case we know the distribution for X is given by:

X \sim N(12,0.3)  

Where \mu=12 and \sigma=0.3

For this case we select 6 cans and we are interested in the probability that the total would be less or equal than 72 ounces. So we need to find a distribution for the total.

The definition of sample mean is given by:

\bar X = \frac{\sum_{i=1}^n X_i}{n} = \frac{T}{n}

If we solve for the total T we got:

T= n \bar X

For this case then the expected value and variance are given by:

E(T) = n E(\bar X) =n \mu

Var(T) = n^2 Var(\bar X)= n^2 \frac{\sigma^2}{n}= n \sigma^2

And the deviation is just:

Sd(T) = \sqrt{n} \sigma

So then the distribution for the total would be also normal and given by:

T \sim N (\mu = 6*12=72 , \sigma= \sqrt{6} *0.3=0.735)

And we want this probability:

P(T\leq 72)

And we can use the z score formula given by:

z = \frac{x-\mu}{\sigma}

P(T \leq 72) = P(Z< \frac{72-72}{0.735}) = P(Z

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Answer:

They purchased 14 adult tickets and 4 kids tickets.

Step-by-step explanation:

14 x 5 = 70

3x4=12

and then add 70 plus 12 to get 82 dollars.

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