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lyudmila [28]
2 years ago
14

Using a sheet of graph paper, solve the following system of equations graphically. Be sure to show any work, use a straight edge

, and be neat. When you are finished, enter the solution set in the box below and turn in your graph paper to your teacher.
x + y = 0
x - y + 2 = 0

Mathematics
2 answers:
BigorU [14]2 years ago
5 0

we have the following system of equations

x + y = 0\\x - y + 2 = 0

we know that

The intersection of both graphs is the solution of the system of equations

using a graph tool

see the attached figure

the solution is the point (-1,1)

therefore

<u>the answer is</u>

the solution of the system of equations is the point (-1,1)

Angelina_Jolie [31]2 years ago
4 0

Answer:

The solution of given system of equations is (-1,1).

Step-by-step explanation:

The given equation are

x+y=0               ..... (1)

x-y+2=0            ..... (2)

Add both equations.

x+y+x-y+2=0

2x+2=0

Subtract both sides by 2.

2x+2-2=0-2

2x=-2

Divide both sides by 2.

x=-1

Put this value in equation 1.

-1+y=0

Add 1 on the both sides.

-1+y+1=0+1

y=1

Therefore the solution of given system of equations is (-1,1).

Solution of system of equation graphically.

Plot both lines on the graph.

Put x=0, the find the y-intercept of both equations.

(0)+y=0\Rightarrow y=0

Put x=1, the find the y-intercept of both equations.

(1)+y=0\Rightarrow y=-1

Therefore first line passing through the points (0,0) and (1,-1).

Put x=0, the find the y-intercept of both equations.

(0)-y+2=0\Rightarrow y=2

Similarly, put y=0 in second equation.

x-(0)+2=0\Rightarrow x=-2

y-intercept of second equation is (-2,0).

Therefore second line passing through the points (0,2) and (-2,0).

From the graph it is noticed that both the line intersect on the point (-1,1), therefore  solution of given system of equations is (-1,1).

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Thirty percent of the students in a high school face a disciplinary action of some kind before they graduate. Of those students,
MAXImum [283]

Answer:

D. 54%

Step-by-step explanation:

For simplicity, lets assume we have 100 students in high school.

30% of students face disciplinary action, therefore;

⇒ (30/100) x 100 = 30 students.

of these 30 students, 40% go to college. therefore;

⇒ (40/100) x 30 = 12 students (go to college)

Also 70% of students do not face disciplinary action, therefore;

⇒ (70/100) x 100 = 70 students.

of these 70 students. 60% go to college. therefore;

⇒ (60/100) x 70 = 42 students (go to college)

Total number of students who go to college

⇒ 12 + 42 =  54 students

% of students who go to college

⇒ 54/100 = 54%

7 0
2 years ago
Three percent of Jennie’s skin cells were burned when she escaped from a fire. If 3.7×10’(of her skin cells were burned then, ho
lora16 [44]

Answer:

The quantity of Jennie's skin cell were not burned is 119.601 × 10^{10}  .

Step-by-step explanation:

Given as :

The percentage of Jennie's skin cell were burned = 3 %

The quantity of Jennie's skin cell were burned = 3.7 × 10^{10}

Let The quantity of Jennie's skin cell were not burned = x

Let Total quantity of whole skin cell = n

<u>Now, According to question</u>

The quantity of Jennie's skin cell were burned = Total quantity of whole skin cell × percentage of Jennie's skin cell were burned

i.e 3.7 × 10^{10} = n × 3 %

Or, 3.7 × 10^{10} = n × \dfrac{3}{100}

Or, n =  3.7 × 10^{10} × \dfrac{100}{3}

Or, n = \frac{3.7\times 10^{12}}{3}

i.e n = 1.233 × 10^{12}

Or, Total quantity of whole skin cell = n = 1.233 × 10^{12}

<u>Now, Again</u>

∵ percentage of Jennie's skin cell were burned = 3 %

So, percentage of Jennie's skin cell were not burned = 100 % - 3 % = 97 %

so , The quantity of Jennie's skin cell were not burned = 97 % of Total quantity of whole skin cell

Or, x = \frac{97}{100} × n

Or, x =  \frac{97}{100} × 1.233 × 10^{12}

∴ x = 119.601 × 10^{10}

So, The quantity of Jennie's skin cell were not burned = x = 119.601 × 10^{10}

Hence,  The quantity of Jennie's skin cell were not burned is 119.601 × 10^{10}  . Answer

6 0
2 years ago
1. In a batch of 10 items, we wish to extract a sample of 3 without replacement. How many
svetlana [45]

Answer:

1) 120

2) E (Z) = 12 and Variance of Z = 90

a) 5 liters

Step-by-step explanation:

1. We can find this by suing combinations.

Here n= 10 and r= 3 so n C r

= 10 C 3= 120

2. E(X) = 8 and E(Y) = 3

Z = 2X - 3Y +5

E(Z ) = 2 E (X) - 3(E)(Y) +5   ( applying property for mean)

       = 2(8) - 3(3)+ 5 = 16+5-9= 21-9= 12

V(X) = 9 and V(Y) = 6.

V(Z) = E(Z )²-  V(X) *V(Y)   (applying property for Variance for two variables )

        = 144- 54= 90

3. 55 liters contain adulterated milk in 7: 4.

So it contains 4/ 11*55= 20 liters of water

But we want to make it a ratio of 7:6

the water will be 6/13 *55= 25.38 when rounded gives 25 liters of water

So 25- 20 = 5 liters must be added to make it a ratio of 7:6

6 0
2 years ago
HELP I WILL NAME YOU BRAINLIEST!! Given: Circumscribed polygon ACEG B, H, F, D -points of tangency AB=5, CD=4, DE=3, FG=2 Find:
wolverine [178]

Answer:

perimeter = 28

Step-by-step explanation:

Tangents drawn to a circle from an external point are congruent, thus

AH = AB = 5

GH = GF = 2

EF = ED = 3

CB = CD = 4

Sum the 8 parts for perimeter of polygon ACEG

perimeter = 5 + 5 + 2 + 2 + 3 + 3 + 4 + 4 = 28

4 0
2 years ago
A standard piece of paper is 0.05 mm thick. Let's imagine taking a piece of paper and folding the paper in half multiple times.
kobusy [5.1K]

Answer:

  g(n) = 0.05·2^n

Step-by-step explanation:

The paper with no folds is 0.05 mm thick. Each fold multiplies the thickness by 2, so the function is ...

  g(n) = 0.05·2^n

_____

<em>Comment on paper folding</em>

In practice, where the paper must bend around the fold, it is impossible to fold an ordinary piece of paper 9 times. You may be able to fold a very large, very thin piece of paper that many times.

8 0
2 years ago
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