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1 year ago

What is the sum of StartRoot negative 2 EndRoot and StartRoot negative 18 EndRoot?

Mathematics

1 answer:

Darya [45]1 year ago

3 0

Answer:

$4 \sqrt{2} i$

Step-by-step explanation:

We want to find the sum of

$\sqrt{ - 2} + \sqrt{ - 18}$

We can rewrite this as

$\sqrt{ 2 \times - 1} + \sqrt{ 18 \times - 1}$

This becomes;

$\sqrt{2} \times \sqrt{ - 1} + \sqrt{18} \times \sqrt{ - 1}$

Recall that;

$i = \sqrt{ - 1}$

This implies that;

$\sqrt{2} i + 3 \sqrt{2} i$

Combine like terms:

$4 \sqrt{2} i$

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or the past 50 days, daily sales of laundry detergent in a large grocery store have been recorded (to the nearest 10). Units Sol

bagirrra123 [75]

Answer, step-by-step explanation:

A. With the previous exercise we can deduce that there is the situation of a number of sales in a grocery store, the relative frequency for the number of units sold, is shown below:

units sold. relative frequency. Acumulative frequency. interval of random numbers

30. 0.16. 0.16. 0.00 <0.16

40. 0.24. 0.4. 0.16 <0.4

50. 0.3. 0.7. 0.4 <0.7

60. 0.2. 0.9. 0.7<09

70. 0.1. 1. 0.9<1

B. For the next point, they give us some random numbers and then it is compared with the simulation of 10 days in sales:

random Units

number. sold

0.12. 30

0.96. 70

0.53. 50

0.80. 60

0.95. 70

0.10. 30

0.40. 50

0.45. 50

0.77. 60

0.29. 40

the two lists are compared so that opposite each one is the result of the simulation

3 0

1 year ago

An airplane is flying at a speed of 500 mi/h at an altitude of one mile. The plane passes directly above a radar station at time

d1i1m1o1n [39]

Answer:

a) $s=\sqrt{1+d^2}$

b)d(t)=500t

c) $s(t) =\sqrt{1+250000t^2}$

Step-by-step explanation:

d = Horizontal distance

s = the distance between the plane and the radar station

The horizontal distance (d), the one mile altitude, and s form a right triangle.

So, use Pythagoras theorem

$Hypotenuse^2=Perpendicular^2+Base^2$

$s^2=1^2+d^2$

a) $s=\sqrt{1+d^2}$

(b) Express d as a function of the time t (in hours) that the plane has flown.

$distance = speed \times time$

d(t)=500t

$s(t) =\sqrt{1+d^2}$

using b

$s(t) =\sqrt{1+(500t)^2}\\s(t) =\sqrt{1+250000t^2}$

6 0

1 year ago

The Goodsmell perfume producing company has a new line of perfume and is

LenKa [72]

Given:

It is given that surface area must be less than 150 cm².

Solution:

The Maximum Volume With Total Surface Area Less than 150 cm² is shown in the table.

From the table, it can be concluded that for r=3.00 cm and h=4.95 cm the surface area will be less than 150 cm² and the volume will be the maximum.

$S=2\pi rh+2\pi r^2\\S=2\pi (3)(7.95)+2\pi3^2\\S=93.3+56.5\\S=149.8 \text{ cm}^2$

Calculate the volume.

$V=\pi r^2h\\V=\pi(3)^2(4.95)\\V=139.96$

Hence, the required dimensions are r=3.00 cm and h=4.95 cm.

8 0

2 years ago

The circumference of a tire is 96 inches. Determine the radius of the tire use 3 for pie

masya89 [10]

Circumference = 2*pi*radius.

Pi = 3.

2 * pi * r = 96

2 * 3 = 6.

2 * 3 * r = 96

Find r: 96/6 = 16.

2 * 3 *16 = 96.

r = 16.

7 0

1 year ago

What is 6.8784 rounded to the nearest thousandth?

mixas84 [53]

Answer:

6.878

Step-by-step explanation:

I took the quiz

5 0

2 years ago