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Korvikt [17]
1 year ago
5

Suppose that a person's birthday is a uniformly random choice from the 365 days of a year (leap years are ignored), and one pers

on's birthday is independent of the birthdays of other people. alex, betty and conlin are comparing birthdays. define these three events: a = {alex and betty have the same birthday} b = {betty and conlin have the same birthday} c = {conlin and alex have the same birthday} are these events independent ?
Mathematics
1 answer:
maxonik [38]1 year ago
3 0
P ( A ∩ B ∩ C) = 1/365
P(A) = 1/365, P(B)= 1/365, P(C) = 365
If events A,B and C are independed then P (A ∩ B ∩ C) = P (A) P(B) P(C) must be true,
From the probabilities we have 
1/365≠ 1/365 * 1/365 * 1/365
Thus, events A,B, C are not independent.

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Answer:

The 98% confidence interval would be given by (0.326;0.354)

Step-by-step explanation:

1) Notation and definitions

X=63 number of people who live within 20 miles of the coast in high hurricane risk counties of eight southern states

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p true population proportion of people who live within 20 miles of the coast in high hurricane risk counties of eight southern states

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

2) Confidence interval

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 98% of confidence, our significance level would be given by \alpha=1-0.98=0.02 and \alpha/2 =0.01. And the critical value would be given by:

z_{\alpha/2}=-2.33, z_{1-\alpha/2}=2.33

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

If we replace the values obtained we got:

0.34 - 2.33\sqrt{\frac{0.34(1-0.34)}{6138}}=0.326

0.34 + 2.33\sqrt{\frac{0.34(1-0.34)}{6138}}=0.354

The 98% confidence interval would be given by (0.326;0.354)

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Step-by-step explanation:

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(2x+3y)⁴
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