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nataly862011 [7]
2 years ago
5

Which of the following is the graph of y = negative StartRoot x EndRoot + 1? On a coordinate plane, an absolute value curve curv

es up and to the right in quadrant 4 and starts at y = negative 1. On a coordinate plane, an absolute value curve curves up and to the right in quadrant 4 and starts at y = 1. On a coordinate plane, an absolute value curve opens down and to the left in quadrant 2 and starts at y = 1. On a coordinate plane, an absolute value curve opens down and to the left in quadrant 2 and starts at y = negative 1.
Mathematics
2 answers:
mestny [16]2 years ago
7 0

Answer:

  • B. On a coordinate plane, an absolute value curve curves up and to the right in quadrant 4 and starts at y = 1.

Step-by-step explanation:

<u>Graph of the function:</u>

  • y = -√x + 1

The domain is x ≥ 0, the range y ≤ 1

Correct answer choice is B

  • On a coordinate plane, an absolute value curve curves up and to the right in quadrant 4 and starts at y = 1.

<em>The graph is attached</em>

erica [24]2 years ago
6 0

Answer: it’s B

Step-by-step explanation: got it right on edge 2021

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Slope-intercept form is y = mx +b, where the variable m represents the slope of the line and the variable b represents the y-intercept of the line. Since we weren't given the y-intercept, one way to solve this problem is substitute the slope for the variable m and then the x and y values from the ordered pair to solve for b.

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Now, we can simplify by computing the multiplication on the right side of the equation.

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