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olga nikolaevna [1]
2 years ago
9

Lisa and Daisy work at a hair salon. The salon charges $18 for a hair styling session with Lisa and $12 for a session with Daisy

. The income on a certain day is projected to be $216. This situation can be represented by the equation 18x + 12y = 216, where x is the number of Lisa's customers and y is the number of Daisy's customers. How many customers would Lisa need to serve to attain the projected income if Daisy calls in sick that day? (Note: x ≥ 0, y ≥ 0, and x and y take only integer values.)
Mathematics
1 answer:
Kitty [74]2 years ago
3 0
Our equation is:
18x + 12y = 216

if Daisy calls in sick that day that means that that day she attained y=0 customers. now we need to solve for x.

18x = 216
x = 12

Answer is 12.
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Answer:

We accetp  H₀

Step-by-step explanation:

Information:

Normal distribution  

Population mean      =   μ₀  = 449

Population standard deviation  σ   unknown

Sample size   n  =  23        n < 30    we use t-student test

so   n  =  23    degree of fredom   df = n  - 1  df  = 23- 1   df = 22

Sample mean    μ =  448

Sample standard deviation   s  =  20

Significance level  α  =  0,05  

1.-Hypothesis Test

Null hypothesis                               H₀     μ₀  =  449

Alternative hypothesis                    Hₐ     μ₀  ≠  449

Problem statement ask for determine decision rule for rejecting the null hypothesis. For rejecting the null hypothesis we have to  get an statistic parameter wich implies  that μ is bigger or smaller than μ₀

2.-Significance level   α  =  0,05  ;  as we have a two tail test

α/2    =  0,025

Then from t - student table for  df =  22   and 0,025 (two tail-test)

t(c)  =  ±  2.074

3.- Compute  t(s)

t(s)   =  (  μ  -  μ₀ )  /  s /√n

plugging in values

t(s)   =  (448  -  449) /  20 /√23    ⇒   t(s)   =  -  1*√23 /20

t(s)   =  - 0.2398

4.-Compare t(c)   and  t(s)

t(s)  <  t(c)         - 0.2398  <  - 2.074

Therefore  t(s)  in inside acceptance region.  We accept  H₀

7 0
2 years ago
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emmainna [20.7K]

Answer:

0.5%/year

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Percentage of females by year:

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1990 = 10.8%

2000 = 13.6%

2012 = 21.7%

Average yearly increase :

Percentage increase between 1980 - 2012 :

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Given an average increase of 0.484375% / year

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Hence by 2030 ; ( 50 years × 0.484375%/year) = 24.218% will claim no religious affiliation.

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Answer:

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slope is rise over run.

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8 0
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