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frutty [35]
2 years ago
7

Drag the values to order them from least to greatest, with the least at the top. Item 2 moved to position 3. 79 − − √ + 63 − − √

143 − − − √ 4π Previous
Mathematics
1 answer:
Nonamiya [84]2 years ago
7 0

\sqrt{63} \\ \\ \sqrt{79}  \\ \\ \sqrt{143} \\ \\ 4\pi

<h2>Explanation:</h2>

As I understand, in this exercise, we have the following numbers:

\text{Number 1}=\sqrt{79} \\ \\ \text{Number 2}=\sqrt{63} \\ \\ \text{Number 3}=\sqrt{143} \\ \\ \text{Number 4}=4\pi

By using calculator, let's convert those numbers into decimal form:

\text{Number 1} \approx 8.88\\ \\ \text{Number 2} \approx 7.93 \\ \\ \text{Number 3} \approx 11.96 \\ \\ \text{Number 4} \approx 12.56

So arranging from least to greatest we have:

\text{Number 2} \\ \\ \text{Number 1} \\ \\ \text{Number 3} \\ \\ \text{Number 2}

Put another way:

\sqrt{63} \\ \\ \sqrt{79}  \\ \\ \sqrt{143} \\ \\ 4\pi

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A running coach wants to know if participating in weekly running clubs significantly improves the time to run a mile. The runnin
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Answer:

Option B is correct.

Use the difference in sample means (10 and 8) in a hypothesis test for a difference in two population means.

Step-by-step Explanation:

The clear, complete table For this question is presented in the attached image to this solution.

It should be noted that For this question, the running coach wants to test if participating in weekly running clubs significantly improves the time to run a mile.

In the data setup, the mean time to run a mile in January for those that participate in weekly running clubs and those that do not was provided.

The mean time to run a mile in June too is provided for those that participate in weekly running clubs and those that do not.

Then the difference in the mean time to run a mile in January and June for the two classes (those that participate in weekly running clubs and those that do not) is also provided.

Since, the aim of the running coach is to test if participating in weekly running clubs significantly improves the time to run a mile, so, it is logical that it is the improvements in running times for the two groups that should be compared.

Hence, we should use the difference in sample means (10 and 8) in a hypothesis test for a difference in two population means.

Hope this Helps!!!

7 0
2 years ago
A pound of oranges costs $2 less than a pound of pears. Together, ten pounds of oranges and eight pounds of pears cost $61. How
Thepotemich [5.8K]

Let us say that:

o = cost of oranges per pound

p = cost of pears per pound

 

so that:

o = p – 2

 

Therefore:

10o + 8p = 61

10 (p – 2) + 8p = 61

10p – 20 + 8p = 61

18p = 81

p = 4.5

p = $4.5 per pound

 

So 3 pounds of pears would cost:

total cost = 3 * 4.5

total cost = $13.5

3 0
2 years ago
Justin is constructing a line through point Q that is perpendicular to line n. He has already constructed the arcs shown. A line
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I believe that this problem has the following choices:

It must be equal to BQ .<span>
It must be wider than when he constructed the arc centered at point A.
It must be equal to AB .
It must be the same as when he constructed the arc centered at point A.</span>

 

The correct answer is the last one:

It must be the same as when he constructed the arc centered at point A.

<span> </span>

4 0
2 years ago
Read 2 more answers
How far should Galileo walk up the inclined plane?
sergejj [24]

Answer:

Step-by-step explanation:

150/x=sin 15

x=150/sin 15 ≈579.56 m

4 0
2 years ago
A piggy bank contains some dimes and nickels. There are 8 more dimes than nickels in the bank. There is a total of $1.40. How ma
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Answer:

4 nickels

12 dimes

Step-by-step explanation:

Dimes are worth .1 each while nickels are .05 each.

We have 8 more dimes than nickels. Let d represent number of dimes and n for number of nickels. This means we have d=8+n.

If all our nickels and dimes together are worth 1.4 then we have another equation .1d+.05n=1.4

Lets put our equations together:

d=8+n

.1d+.05n=1.4

‐-----------------Plug first equation into second.

.1(8+n)+.05n=1.4

Distribute

.8+.1n+.05n=1.4

Combine like terms

.8+.15n=1.4

Subtract .8 on both sides

.15n=.6

Divide both sides by .15

n=.6/.15=4

Remember there are 8 more dimes so d=8+4=12.

5 0
2 years ago
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