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uranmaximum [27]
2 years ago
11

Which measurement is the best estimate for the capacity of a bottle of nail polish?

Mathematics
1 answer:
Law Incorporation [45]2 years ago
4 0
The best estimate for the capacity of a bottle of nail polish is A: 10 mL
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How will the metric system be used in your furture career
Solnce55 [7]

Answer:

i feel as if in the United States, both the metric system and the English system of measurement are used, although the English system predominates. This discussion question has three parts:

Look around you to find something in the U.S. that is measured in metrics. Describe it to the class.

Give an example of how you think the metric system will be used in your future career.

Do you think the U.S. should switch to metric system exclusively? Why or why not?

This week we learned about the metric and U.S. customary measurement systems. Please upload and submit your responses to the following questions in at least 150 words:

In reflecting on both measurement systems, what did you find most important?

Explain how both measurement systems could relate to your life, community, or current/future career.

Expert Answer

Step-by-step explanation:

6 0
2 years ago
A team is selling discount cards as a fundraiser. The table shows the number of cards sold and the remaining amount of money nee
Nimfa-mama [501]

Answer:it’s negative

Step-by-step explanation:

Edge 2020

4 0
2 years ago
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Estimate 1/5 percent of 201
mote1985 [20]
If you would like to estimate 1/5 percent of 201, you can calculate this using the following steps:

1/5 percent of 201 = 1/5% of 201 = 1/5% * 201 = 1/5 / 100 * 201 = 1/500 * 201 = 201/500 = 0.402

Result: 1/5 percent of 201 is 0.402.
7 0
1 year ago
Assume that the number of hours of daylight in New Orleans in 1994 is given by the function D(x) = 7 3 sin 2π 365 x + 35 3 , whe
Bas_tet [7]

Answer:

Here, the given function that represents the number of hours of daylight in New Orleans in 1994 is,

D(x) = \frac{7}{3} \sin \frac{2\pi }{365}x + \frac{35}{3}

Where,

x = the number of days after March 21

The number of days from 1 January to march 21 = 80

If x = -80, then,

D(-80) = \frac{7}{3} \sin \frac{2\pi }{365}(-80) + \frac{35}{3}

            =\frac{7}{3} \sin (-\frac{160 \pi}{365}) + \frac{35}{3}

            =-\frac{7}{3} \sin (\frac{160 \pi}{365}) + \frac{35}{3}

            =-\frac{7}{3}(0.98130)+\frac{35}{3}

           \approx 9.38

Therefore, the number of hours of daylight on January 1 are 9.38.

The number of days from march 21 to may 4 = 44

If x =44, then,

D(44) = \frac{7}{3} \sin \frac{2 \pi}{365}(44) + \frac{35}{3}

         =\frac{7}{3} \sin (\frac{88 \pi}{365}) + \frac{35}{3}

         =\frac{7}{3}(0.6870) + \frac{35}{3}

         \approx 13.27

Therefore, the number of hours of daylight on May 4 are 13.27.

The number of days from October 28 to may 4 = 221

If x = 221, then,

D(221) = \frac{7}{3} \sin \frac{2 \pi}{365}(221) + \frac{35}{3}

           =\frac{7}{3} \sin (\frac{442 \pi}{365}) + \frac{35}{3}

           =\frac{7}{3}(-0.6152)+\frac{35}{3}

           \approx 10.23

Therefore, the number of hours of daylight on October 28 are 10.23.

4 0
1 year ago
Find all explicit solutions y = ϕ(x) of the DE in part (a) defined by this relation. Give the interval I of definition of each e
Evgen [1.6K]

Answer and Step-by-step explanation:

Firstly, by definition, an interval of definition of any solution is the open interval on which it is defined.

Consider the problem p′=p², p(0)=1, has solution p(t) = 1/(1−t).

The definition of this solution is on the interval (−1/2,1/3), making it an interval of definition of solution.

However, it isn't the largest. The largest interval of definition is (−∞,1).

Consider another problem: p(t)=t√ satisfies the ODE p′=1/(2p).

Meanwhile, when considered as the solution of the ODE above, the domain of square root is [0,∞), and the interval of definition is (0,∞).

But at t=0 the ODE makes no sense, so it would be wrong to assume that y satisfies the ODE in this case. Meanwhile, ODEs are generally considered only on open intervals.

7 0
1 year ago
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