Answer:
StartRoot 53 EndRoot units
XY = √53
Step-by-step explanation:
Choose which is point 1 and point 2 so you don't confuse the coordinates.
Point 1 (–4, 0) x₁ = –4 y₁ = 0
Point 2 (3, 2) x₂ = 3 y₂ = 2
Use the formula for the distance between two points.
Therefore the line of segment XY is √53.
<span>Logarithm form is another way to express a number in exponential (exp.) form. log 8 (2) is the same as 8 (x) = 2 or in words, eight with exp. x equals two. If we take that equation and cube both sides, or raise each side to the power of 3, [8 (x)] with exp. 3 = 2 with exp. 3. This simplifies to 8 (3x) = 8. By definition, 8 is the same as 8 with exp. 1. So the equation is now 8 (3x) = 8 (1). This means 3x = 1. We can simplify to x = 1/3.</span>
So, we're finding ratios first okay, for every 4ft:12in and 6ft:18in so for every one foot there is 3 inches which is your rate of incline 1:3 or every one foot there are 3 inches of incline hope this helped you have an amazing day
Let F be the father's current age, and E be Evie's current age.
F = E + 36 this is the current relation between the ages
F + 3 = 5(E + 3) this the relationship in 3 year (hence the + 3)
Then solve by substituting one equation into another:
(E + 36) + 3 = 5(E + 3)
E + 39 = 5E + 15
24 = 4E
6 = E
Evie's current age is 6.
Answer: In the beginning he was given 27 sweets.
Step-by-step explanation: The most logical thing to do is to solve it backwards, that is, from what he had at the end of the third day up till the beginning of the first day.
On the third day he ate one-third and had 8 sweets left over. To determine how many he started with on the third day, let the total on day three be called a. If one-third of a is eaten, then the left over which is two-thirds is 8. That is;
8/a = 2/3
By cross multiplication we now have
8 x 3 = 2a
24/2 = a
a = 12
Let the number of sweets he had on day two be called b. If he ate one-third of b and he had 12 left over, then the two-thirds left over is 12 and we now have;
12/b = 2/3
By cross multiplication we now have
12 x 3 = 2b
36 = 2b
36/2 = b
b = 18
Let the number of sweets he had on day one be called x. If he ate one-third of x and he had 18 left over, then the two-thirds left over is 18, and we now have;
18/x = 2/3
By cross multiplication we now have
18 x 3 = 2x
54 = 2x
x = 27
Therefore Tim was given 27 sweets at the beginning.
