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8_murik_8 [283]
1 year ago
8

Given EP = FP and GQ = FQ, what is the perimeter of ΔEFG?

Mathematics
1 answer:
eduard1 year ago
5 0

x is  \frac{2y + 1}{2y - 3}

<u>Explanation:</u>

Given:

EP = FP

GQ = FQ

Since the sides are equal, the ΔFPQ and ΔFEG are similar.

According to the property of similarity:

\frac{FP}{PE} =\frac{FQ}{QG}

On substituting the value:

\frac{2x}{4y+2} = \frac{3x-1}{4y + 4} \\\\2x ( 4y + 4) = (3x-1)(4y+2)\\\\8xy + 8x = 12xy + 6x - 4y - 2\\\\4xy - 6x - 4y - 2 = 0\\\\2xy - 3x - 2y - 1 = 0\\\\2xy - 3x = 2y + 1\\\\x(2y - 3) = 2y +1\\\\x = \frac{2y+1}{2y-3}

Perimeter will be sum of all the sides. If y is known then substitute the value and then find the perimeter.

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5 0
1 year ago
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Answer:

Here is the question attached with.

m\angle CEA =90 \ (deg)

m\angle BEF=135\ (deg)

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Step-by-step explanation:

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