Answer:
The correct option is D) 47,063 and 54,722.
Step-by-step explanation:
Consider the provided information.
Here we need to find the number pair that has digits of 4 that differ in place by a factor of 1000.
Now consider the option A) 49,823 and 81,540
The place value of 4 in 49,823 and 81,540 is 40,000 and 40 respectively.
So the difference=40,000-40=39960 which is not a multiple of 1000.
Consider the option B) 83,419 and 46,859
The place value of 4 in 83,419 and 46,859 is 400 and 40,000 respectively.
So the difference=40,000-400=39600 which is not a multiple of 1000.
Consider the option C) 54,890 and 81,745
The place value of 4 in 54,890 and 81,745 is 4000 and 40 respectively.
So the difference=4000-40=3960 which is not a multiple of 1000.
Consider the option D) 47,063 and 54,722
The place value of 4 in 47,063 and 54,722 is 40,000 and 4000 respectively.
So the difference=40000-4000=36000 which is a multiple of 1000.
Hence, the correct option is D) 47,063 and 54,722.
