we know that
The measurement of <u>the external angle</u> is the semi-difference of the arcs it includes.
In this problem
![21\°=\frac{1}{2}[arc\ RU-arc\ SU]](https://tex.z-dn.net/?f=21%5C%C2%B0%3D%5Cfrac%7B1%7D%7B2%7D%5Barc%5C%20RU-arc%5C%20SU%5D)
Solve for the measure of arc SU
![42\°=[arc\ RU-arc\ SU]](https://tex.z-dn.net/?f=42%5C%C2%B0%3D%5Barc%5C%20RU-arc%5C%20SU%5D)


therefore
the answer is
The measure of the arc SU is 
Answer: Magnitude of wx is 
Step-by-step explanation:
Since we have given that

Now, first we will find 'wx':

We need to find the "magnitude":

Hence, Magnitude of wx is 
Answer:
18,354 - 4,672= 13,682
Step-by-step explanation:
I'm not sure what you meant but above is the answer of what I think you were asking.