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Nataly [62]
2 years ago
15

Choose the number pair that has digits of 4 that differ in place by a factor of 1000. 4 A. 49,823 and 81,540 B. 83,419 and 46,85

9 C. 54,890 and 81,745 D. 47,063 and 54,722 4.NBT.1
Mathematics
1 answer:
Ne4ueva [31]2 years ago
3 0

Answer:

The correct option is D) 47,063 and 54,722.

Step-by-step explanation:

Consider the provided information.

Here we need to find the number pair that has digits of 4 that differ in place by a factor of 1000.

Now consider the option A) 49,823 and 81,540

The place value of 4 in 49,823 and 81,540 is 40,000 and 40 respectively.

So the difference=40,000-40=39960 which is not a multiple of 1000.

Consider the option B) 83,419 and 46,859

The place value of 4 in 83,419 and 46,859 is 400 and 40,000 respectively.

So the difference=40,000-400=39600 which is not a multiple of 1000.

Consider the option C) 54,890 and 81,745

The place value of 4 in 54,890 and 81,745 is 4000 and 40 respectively.

So the difference=4000-40=3960 which is not a multiple of 1000.

Consider the option D) 47,063 and 54,722

The place value of 4 in 47,063 and 54,722 is 40,000 and 4000 respectively.

So the difference=40000-4000=36000 which is a multiple of 1000.

Hence, the correct option is D) 47,063 and 54,722.

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