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Allushta [10]
1 year ago
12

You and your friend each collect rocks and fossils. Your friend collects three times as many rocks and half as many fossils as y

ou. You collect 20 objects. Your friend collects 20 objects. How many rocks and how many fossils do you each collect?
Mathematics
1 answer:
pochemuha1 year ago
4 0

Answer:

I collect 4 rocks and 16 fossils. While my friend collects 12 rocks and 8 fossils.

Step-by-step explanation:

The number of total objects collected by me  = 20

The number of objects collected by my friend  = 20

Let us assume:

The number of rocks collected by me  = m

The number of fossils collected by me  = 2 k

⇒ m +  2 k =  20  .... (1)

So, according to the question:

The number of rocks collected by my friend = 3 x (rocks collected by me)  

= 3 x (m)  = 3 m

The number of fossils collected by my friend = 1/2 x (fossils collected by me)    = 1/2 x (2k )  = k

⇒ 3 m +   k =  20  .... (2)

Solving (1)and (2) for the value of m and k, we get:

m +  2 k =  20     ⇒ m = 20 - 2 k ... Put this in (2)

3 m +   k =  20  ⇒  3 (20 - 2 k) +  k = 20

⇒ 60 - 6 k +  k  = 20

or, - 5k = -40

or, k = 40/5  = 8

⇒ k= 8

m + 2(8)  = 20

or, m = 4

Hence, the number of rocks collected by me  = m = 4

The number of fossils collected by me  =  2 k = 2 (4)  = 16

Hence, the number of rocks collected by my friend   = 3 m  = 3 x 4 = 12

The number of fossils collected by my friend   =   k =  8

Hence, I collect 4 rocks and 16 fossils. While my friend collects 12 rocks and 8 fossils.

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Answer:

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Step-by-step explanation:

Notation

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Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

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For this case the  95% confidence interval is given (63.5 , 74.4) and we want to conclude about the result. For this case we can say that the true mean of heights for male students would be between 63.5 and 74.4. And the best answer would be:

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Explanation :

Since we have given that

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