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1 year ago

Solve the equation using square roots. 7x2 + 6 = 13

Mathematics

2 answers:

m_a_m_a [10]1 year ago

8 0

Answer:

The solution of the equation $7x^2+6=13$ is:

x=1 or -1

Step-by-step explanation:

$7x^2+6=13$

subtracting by 6 on both sides

$7x^2+6-6=13-6$

$7x^2=7$

dividing by 7 on both sides, we get

$x^2=1$

taking square roots on both sides, we get

x=±√1

⇒ x=1 or -1

Elis [28]1 year ago

4 0

Move all terms not containing xx to the right side of the equation.
Since 66 does not contain the variable to solve for, move it to the right side of the equation by subtracting 66 from both sides.7x2=−6+137x2=-6+13Add −6-6 and 1313 to get 77.7x2=77x2=7Divide each term by 77 and simplify.
Divide each term in 7x2=77x2=7 by 77.7x27=777x27=77Reduce the expression by cancelling the common factors.
x2=77x2=77Divide 77 by 77 to get 11.x2=1x2=1Take the squaresquare root of both sides of the equationequation to eliminate the exponent on the left side.x=±√1x=±1The complete solution is the result of both the positive and negative portions of the solution.
Any root of 11 is 11.x=±1x=±1The complete solution is the result of both the positive and negative portions of the solution.
x=1,−1

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Given: EL- tangent, EK- secant Prove: EJ·LK = EL·LJ

drek231 [11]

Answer:

This is possible.

Step-by-step explanation:

We can say that m<E=m<E, because of the Reflexive Property

Then, we have angles JKL and ELJ, which are equal through the peripheral angle theorem.

With these two angles, we can say that triangles ELK and EJL are similar, by the Angle-Angle Postulate (AA).

Then we can create this ratio through the Corresponding Parts of Similar Triangles Theorem, (CPST), $\frac{LK}{LJ} =\frac{EL}{EJ}$ .

With this ratio, we can cross multiply to get the desired result

$EJ$ · $LK=EL$ · $LJ$

Hope this helps with your RSM problem

Yup, i caught ya.

3 0

2 years ago

Find the quantity q that maximizes profit if the total revenue, R(q), and total cost, C(q) are given in dollars by R(q)=3q−0.002

marysya [2.9K]

Answer:

The value of q that maximize the profit is q=200 units

Step-by-step explanation:

we know that

The profit is equal to the revenue minus the cost

we have

$R(q)=3q-0.002q^{2}$ ---> the revenue

$C(q)=200+2.2q$ ---> the cost

The profit P(q) is equal to

$P(q)=R(q)-C(q)$

substitute the given values

$P(q)=(3q-0.002q^{2})-(200+2.2q)$

$P(q)=3q-0.002q^{2}-200-2.2q$

$P(q)=-0.002q^{2}+0.8q-200$

This is a vertical parabola open downward (because the leading coefficient is negative)

The vertex represent a maximum

The x-coordinate of the vertex represent the value of q that maximize the profit

The y-coordinate of the vertex represent the maximum profit

using a graphing tool

Graph the quadratic equation

The vertex is the point (200,-120)

see the attached figure

therefore

The value of q that maximize the profit is q=200 units

6 0

2 years ago

Susan keeps track of the number of tickets sold for each play presented at the community theater. within how many standard devia

Citrus2011 [14]

The Mean = (135 + 71 + 69 + 80 + 158 + 152 + 161 + 96 + 122 + 118 + 87 + 85 ) : 12 = 111.166
The smallest value : 69
The greatest value : 161
s² = ∑( x i - x )² / ( n - 1 )
s² = ( 568.274 + 1613.3 + 1777.97 + 971.32 + 2193.42 + 1667.4 + +2483.42 + 230 + 117.38 + 46.7 + 584 + 684.66 ) : 11
s² = 1176.1676
s = √s² = √1176.1676
s ( Standard deviation ) = 34.295
All the values fall within 2 standard deviations:
x (Mean) - 2 s and x + 2 s

3 0

1 year ago

Read 2 more answers

If four is half of five and two thirds of six is nine. what is thirty-two?

valkas [14]

Four is IV which is half of five. IX is nine which is 2 thirds of 6 so... thirty-two is 1 5/6

5 0

1 year ago

A jar of 150 jelly beans contains 22 red jelly beans, 38 yellow, 20 green, 28 purple, 26 blue, and the rest are orange.Let B = t

pentagon [3]

Answer:

$P(R\ and\ B) = 0.0256$

Step-by-step explanation:

Given

$Red = 22$

$Yellow = 38$

$Green = 20$

$Purple = 28$

$Blue = 26$

$Orange = 16$

Required

Determine the probability of red then blue jelly? i.e. P(R and B)

From the question, we understand that the red jelly bean was not replaced. This means that the number of jelly beans reduced by 1 after the picking of the red jelly bean

So, we have:

$P(R\ and\ B) = P(R)\ and\ P(B)$