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Ira Lisetskai [31]
1 year ago
7

.072 divided by 345.00 and round to the nearest tenth. Thank you!

Mathematics
2 answers:
svp [43]1 year ago
5 0

.072 / 345.00 = 0.0002086956

 the tenth place is the fist digit to the right of the decimal point

 so it would round to 0.0

alexandr402 [8]1 year ago
3 0
0.072 ÷ 345

= \frac{0.072}{345} = 0.000208695652174 ≈ 0.00020
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Ok so
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costused=(number of months) times (cost per month)
if we represent number of months as x
we know cost per month is 18
18x is costused
 and in 2 m onts, he paid 81 so
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2 monts so x=2
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A circular pond is to be surrounded by a gravel path. Use the diagram to find the square feet of gravel needed if we know the po
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I think the correct answer is 70,650 ft², but I would make sure with someone else just in case. 

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1 year ago
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Which relationships have the same constant of proportionality between y and x as in the equation y=1/3x?
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Employment data at a large company reveal that 74% of the workers are married, 42% are college graduates, and that 56% are marri
ValentinkaMS [17]

Answer:

(E) None of these above are true.

Step-by-step explanation:

Married = 74% or 0.74

College graduates = 42% or 0.42

pr(married | college graduates) = 0.56

(A) These events are pairwise disjoint. This is false. Pairwise disjoint are also known as mutually exclusive events. Here we can see that both events are occurring at same time.

(B) These events are independent events. This is also false.

(C) These events are both independent and pairwise disjoint. False

(D) A worker is either married or a college graduate always. False

Here Probability(A or B) shall be 1

= Pr(A) + Pr(B) - Pr( A and B) = 0.74 + 0.42 - 0.56 * 0.42 = 0.9248

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(E) None of these above are true. This is true.

8 0
2 years ago
High school students across the nation compete in a financial capability challenge each year by taking a National Financial Capa
zalisa [80]

Answer:

The students have to score 0.74 standard deviations above the mean to be publicly recognized.

Step-by-step explanation:

A random variable <em>X</em> is said to have a normal distribution with parameters <em>µ</em>    (mean) and <em>σ</em>² (variance).

If X \sim N (\mu, \sigma^{2}), then z=\frac{X-\mu}{\sigma}, is a standard normal variate with mean, E (<em>Z</em>) = 0 and Var (<em>Z</em>) = 1. That is, Z \sim N (0, 1).

The distribution of these <em>z</em>-scores is known as the standard normal distribution.

The <em>z</em>-score is a standardized form of the raw score, <em>X</em>. It is a numerical measurement of the relationship between a value (<em>X</em>) and the mean (<em>µ</em>) in terms of the standard deviation (<em>σ</em>). A <em>z</em>-score of -1 implies that the data value is 1 standard deviation below the mean. And a <em>z</em>-score of 1 implies that the data value is 1 standard deviation above the mean.

Let <em>X</em>  be defined as the scores of students at the National Financial Capability Challenge Exam.

It is provided that the students who score in the top 23% are recognized publicly for their achievement by the Department of the Treasury.

That is, P (X > x) = 0.23.

⇒ P(\frac{X-\mu}{\sigma}>\frac{x-\mu}{\sigma})=0.23

⇒

   P(Z>z)=0.23\\1-P(Z

The value of <em>z</em> for this probability value is:

<em>z</em> = 0.74.

*Use a <em>z</em>-table.

Thus, the students have to score 0.74 standard deviations above the mean to be publicly recognized.

8 0
2 years ago
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