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2 years ago

1+4=5; 2+5=12; 3+6=21; 8+11=?

2 answers:

3 0

The pattern:
So it goes, 1, 2, 3, as the first number in each equation right.
Then it goes 4,5,6 as the second number in each equation.
In other words, the first number + 3 = the second number

The sum or 3rd number is a zig zag pattern from the first and second numbers as shown below.
1 2 3 4 5 6 7 8 9
4 5 6 7 8 9 10 11 12

1 * 5 = 5, 2 * 6 = 12, 3 * 7 = 21 .... 8 * 12 = 96

So the answer of 8+11=96

Gnom [1K]2 years ago

3 0

8 + 11 = 40. Because, 8+11= 19 and 19 + 21 is 40.

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A 2-column table with 6 rows. The first column is labeled miles driven with entries 27, 65, 83, 109, 142, 175. The second column

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Answer:

1) The linear regression model is y = -0.0348·x + 13.989

2) The correlation coefficient is -0.0725

3) The strength of the model is strong - association

Step-by-step explanation:

X Y XY X²

27 13 351 729

65 12 780 4225

83 11 913 6889

109 10 1090 11881

142 9 1278 20164

175 8 1400 30625

∑ 601 63 5812 74513

From y = ax + b, we have

$a = \frac{n\sum xy - \sum x\sum y }{n\sum x^{2}-\left (\sum x \right )^{2}} = \frac{6 \times 5812 - 601 \times 63}{6 \times 74513-601^{2}} = - 0.0348$

b = 1/n(∑y -a∑x) = 1/6(63 - (0.0348)×601) = 13.989

Therefore, the linear regression model is y = -0.0348·x + 13.989

$r = \frac{n\sum xy - \sum x\sum y }{\sqrt{[n\sum x^{2}-\left (\sum x \right )^{2}] [n\sum y^{2}-\left (\sum y \right )^{2}]}} = \frac{6 \times 5812 - 601 \times 63}{\sqrt{[6 \times 74513-601^{2}] [6 \times 3969 - 63^2]} } = - 0.0725$

3) The strength is - association.

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which has a value of about 5.99086.

Let $f(x)=\sqrt{1+\frac{9x^4}{(6+x^3)^2}}$ . Split up the interval of integration into 10 subintervals,

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It turns out that

$\displaystyle\int_{\ell_i}^{r_i}p_i(x)\,\mathrm dx=\frac{f(\ell_i)+4f(m_i)+f(r_i)}6$

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