Answer:
And the critical value for the significance level used is:
Since the calculated value is less than the critical value we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the College graduation status and cola preference are independent
Step-by-step explanation:
For this case we want to test the following hypothesis:
Null hypothesis: College graduation status and cola preference are independent
Alternative hypothesis: College graduation status and cola preference are dependent
For this case we got a calculated statistic of:
And the critical value for the significance level used is:
Since the calculated value is less than the critical value we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the College graduation status and cola preference are independent
Answer:
0.7673
Step-by-step explanation:
We have the following:
The null and alternative hypothesis is,
H0: m = 290
Ha: m> 290
x = 285.2
m = 290
sd = 59.3
n = 82
is m the mean, sd the standard deviation and n the population size
Now we calculate the value of z like this:
z = (x - m) / sd / (n ^ (1/2))
z = (285.2 - 290) / 59.3 / (82 ^ (1/2))
z = -0.73
now
P (z> -0.73) = 1 - P (z <-0.73)
we look at the normal distribution table
P = 1 - 0.2327 = 0.7673
Therefore the value of p is equal to 0.7673
B
Here, x is the volume of the 10ml solution. Multiplying it by its concentration gives the amount of alcohol in it. 50 is the total volume of the 12% solution so (50 - x) gives the volume of the 15% solution. Multiplying this by the concentration gives the amount of alcohol in it. The sum of these amounts of alcohols is equivalent to the amount of alcohol in the 12% solution which is given by the product of its volume and concentration.
Step-by-step explanation:
-7y > 161
7y < 161
7÷7=1
161÷7=23
y=23
7y > -161
7÷7=1
-161÷7=-23
y=-23
