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2 years ago

14. teacher needs 70 lengths of string cut to 40 cm each. If balls of string are 10m longhow many balls will be needed.

Mathematics

2 answers:

lorasvet [3.4K]2 years ago

7 0

70×40=2800 cm, which would be the total amount of cm that the teacher needs for the balls.

10m = 1000cm

<span> = 2.8</span>

<span>There will be 3 balls of string.</span>

lesantik [10]2 years ago

6 0

70×40=2800cm which is the total amount of cm that the teacher needs

10m = 1000cm

$\frac{2800}{1000}$ = 2.8

there will be 3 balls of string

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Answer:

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Step-by-step explanation:

The equation that models the height of the ball in feet as a function of time is

$h(t) = h_0 + s_0t -16t ^ 2$

Where $h_0$ is the initial height, $s_0$ is the initial velocity and t is the time in seconds.

We know that the initial height is:

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The initial speed is:

$s_0 = 110sin(20\°)\\\\s_0 = 37.62\ ft/s$

So the equation is:

$h (t) = 4.5 + 37.62t -16t ^ 2$

The ball hits the ground when when $h(t) = 0$

$4.5 + 37.62t -16t ^ 2 = 0$

We use the quadratic formula to solve the equation for t

For a quadratic equation of the form

$at^2 +bt + c$

The quadratic formula is:

$t=\frac{-b\±\sqrt{b^2 -4ac}}{2a}$

In this case

$a= -16\\\\b=37.62\\\\c=4.5$

Therefore

$t=\frac{-37.62\±\sqrt{(37.62)^2 -4(-16)(4.5)}}{2(-16)}$

$t_1=-0.114\ s\\\\t_2=2.47\ s$

We take the positive solution.

Finally the ball takes 2.47 seconds to touch the ground

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