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OLEGan [10]
2 years ago
7

In a recent survey ,5 out of every 8 middle school students use a computer to complete school projects .franklin middle school h

as 520 students .based on the results of the survey ,how many students at franklin middle school are expected to use a computer school projects
Mathematics
1 answer:
NeX [460]2 years ago
3 0
The answer i think its 104
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Nina was curious about the height of the Eiffel Tower. She used a 1.2 meter model of the tower and measured its shadow at 2 P.M.
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The blood platelet counts of a group of women have a​ bell-shaped distribution with a mean of 247.9 and a standard deviation of
labwork [276]

Answer:

A) Approximate percentage of women with platelet counts within 2 standard deviations of the​ mean, or between 118.5 and 377.3 = 95%

B) approximate percentage of women with platelet counts between 53.8 and 442.0 = 99.7%

Step-by-step explanation:

We are given;

mean;μ = 247.9

standard deviation;σ = 64.7

A) We want to find the approximate percentage of women with platelet counts within 2 standard deviations of the​ mean, or between 118.5 and 377.3.

Now, from the image attached, we can see that from the empirical curve, the probability of 1 standard deviation from the mean is (34% + 34%) = 68 %.

While probability of 2 standard deviations from the mean is (13.5% + 34% + 34% + 13.5%) = 95%

Thus, approximate percentage of women with platelet counts within 2 standard deviations of the​ mean, or between 118.5 and 377.3 = 95%

B) Now, we want to find the approximate percentage of women with platelet counts between 53.8 and 442.0.

53.8 and 442.0 represents 3 standard deviations from the mean.

Let's confirm that.

Since mean;μ = 247.9

standard deviation;σ = 64.7 ;

μ = 247.9

σ = 64.7

μ + 3σ = 247.9 + 3(64.7) = 442

Also;

μ - 3σ = 247.9 - 3(64.7) = 53.8

Again from the empirical curve attached, we cans that at 3 standard deviations from the mean, we have a percentage probability of;

(2.35% + 13.5% + 34% + 34% + 13.5% + 2.35%) = 99.7%

5 0
2 years ago
A line segment has endpoints at (4, –6) and (0, 2). What is the slope of the given line segment? What is the midpoint of the giv
Sonja [21]

slope = - 2, midpoint = (2, - 2 )

the slope m is calculated using the ' gradient formula '

m = ( y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (4, - 6 ) and (x₂, y₂ ) = (0, 2 )

m = \frac{2+6}{0-4} = \frac{8}{-4} = - 2

calculate midpoint using midpoint formula

{\frac{1}{2} (4 + 0 ), \frac{1}{2} (- 6 + 2 )] = (2, - 2 )

gradient of perpendicular bisector = - \frac{1}{-2} = \frac{1}{2}

equation in slope-intercept form is

y = mx + c ( m is slope and c the y-intercept )

partial equation is y = \frac{1}{2} x + c

to find c substitute ( 2, - 2) into the partial equation

- 2 = 1 + c ⇒ c = - 3

y = \frac{1}{2} x - 3 in slope-intercept form



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Ludmilka [50]
I hope this helps you

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