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2 years ago

7

In a recent survey ,5 out of every 8 middle school students use a computer to complete school projects .franklin middle school h

as 520 students .based on the results of the survey ,how many students at franklin middle school are expected to use a computer school projects

1 answer:

NeX [460]2 years ago

3 0

The answer i think its 104

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Derrick needs to figure out how he’s doing on his test scores so far this year. You can help by calculating the mean and the med

romanna [79]

Answer:

74.4 ,81.5 , median

Step-by-step explanation:

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1 year ago

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Last year, the numbers of skateboards produced per day at a certain factory were normally distributed with a mean of 20,500 skat

BartSMP [9]

Let x be a random variable representing the number of skateboards produced
a.) P(x ≤ 20,555) = P(z ≤ (20,555 - 20,500)/55) = P(z ≤ 1) = 0.84134 = 84.1%

b.) P(x ≥ 20,610) = P(z ≥ (20,610 - 20,500)/55) = P(z ≥ 2) = 1 - P(z < 2) = 1 - 0.97725 = 0.02275 = 2.3%

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2 years ago

Which value of y would make O P is parallel to L N?<br><br> 16<br> 24<br> 32<br> 36

natita [175]

Answer:

Step-by-step explanation:

Triangle proportionality theorem,

$\frac{MO}{OL}=\frac{MP}{PN}\\\\\frac{28}{14}=\frac{y}{18}\\\\\frac{28}{14}*18=y\\\\y=\frac{28}{7}*9\\\\y=4*9\\\\y=36$

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1 year ago

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The weights of certain machine components are normally distributed with a mean of 8.01 g and a standard deviation of 0.06 g. Fin

Free_Kalibri [48]

Answer:

Option D) 7.90 g and 8.12 g

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 8.01 g

Standard Deviation, σ = 0.06 g

We are given that the distribution of weights is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

We have to find the value of x such that the probability is 0.03

P(X > x)

$P( X > x) = P( z > \displaystyle\frac{x - 8.01}{0.06})=0.03$

$= 1 -P( z \leq \displaystyle\frac{x - 8.01}{0.06})=0.03$

$=P( z \leq \displaystyle\frac{x - 8.01}{0.06})=0.97$

Calculation the value from standard normal z table, we have,

$\displaystyle\frac{x - 8.01}{0.06} = 1.881\\\\x = 8.12$

Thus, 8.17 g separates the top 3% of the weights.

P(X < x)

$P( X < x) = P( z < \displaystyle\frac{x - 8.01}{0.06})=0.03$

Calculation the value from standard normal z table, we have,

$\displaystyle\frac{x - 8.01}{0.06} = -1.881\\\\x = 7.90$

Thus, 7.90 separates the bottom 3% of the weights.

Thus, the correct answer is

Option D) 7.90 g and 8.12 g

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2 years ago

What values of b satisfy 4(3b + 2)2 = 64?

Vikentia [17]

Given the equation 4(3b + 2)² = 64, dividing both sides of the equation by 4, we have (3b + 2)² = 16 and getting the square root of both sides, (3b + 2) = 4 and (3b + 2) = -4 We can solve for b for each equation and have 3b = 2 | 3b = -6 b = 2/3 | b = -2 Therefore, the values of b are 2/3 and -2 and from the choices, the answer is <span>A: b = 2/3 and b = -2.</span>

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1 year ago