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2 years ago

How are the two functions f(x) = 0.7(6)x and g(x) = 0.7(6)–x related to each other?

2 answers:

7 0

The answer
f(x) = 0.7(6)x = f(x) = 0.7(6)^x, and g(x) = 0.7(6)–x= g(x) = 0.7(6)^-x=1/0.7(6)^x
so 
g(x) =1/0.7(6)^x=1 /f(x)

 the relationship between f and g are g(x) =1 /f(x) or g(x) . f(x) = 1

zlopas [31]2 years ago

5 0

Answer:

the answer

f(x) = 0.7(6)x = f(x) = 0.7(6)^x, and g(x) = 0.7(6)–x= g(x) = 0.7(6)^-x=1/0.7(6)^x

g(x) =1/0.7(6)^x=1 /f(x)

the relationship between f and g are g(x) =1 /f(x) or g(x) . f(x) = 1

Step-by-step explanation:

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tankabanditka [31]

Answer:

8 < x < 34

Step-by-step explanation:

ab = 13, ac = 21, bc = x

The longest side of a triangle must be less than the sum of the other two sides.

If 21 is the longest side:

21 < 13 + x

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If x is the longest side:

x < 13 + 21

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Therefore, 8 < x < 34.

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2 years ago

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Dima020 [189]

Answer:

x=15

Step-by-step explanation:

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2 years ago

Compute the integral (a) int sin (pi x) dx by letting u = pi x. (b) int e^(x/2) dx by letting u = x/2. Show that you got the cor

Maslowich

Answer:

(a) $\int sin(\pi x) dx$ $=-\frac {cos \pi x}{\pi}+c$

(b) $\int e^\frac{x}{2} dx$ $=2e^\frac{x}{2}+c$

Step-by-step explanation:

(a)

$\int sin(\pi x) dx$

Let u = π x

differentiating with respect to x

du = π dx

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Putting the value of x and dx

$=\int sin u \frac{du}{\pi}$

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Now putting the value of u

$=-\frac {cos \pi x}{\pi}+c$

(b)

$\int e^\frac{x}{2} dx$

Let $u=\frac{x}{2}$

differentiating with respect to x

$du= \frac{1}{2} dx$

2du = dx

Putting the value of x and dx

= $\int e^u.2.du$

= $2e^u +c$

Now putting the value of u

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2 years ago

Timothy wants to estimate the mean number of siblings for each student in his school. He records the number of siblings for each

Ede4ka [16]

Answer:

(A) the specific number of siblings for each randomly selected student

Step-by-step explanation:

First Timothy wants to estimate the mean number of siblings for each student in his school

So he selected a random sample of 75 students, then recorded the number of siblings they have

He later find the mean.

You can see the mean was obtained from the selected group not all students in the school hence option D and E are not correct.

Option A clearly indicates a mean was obtained for the siblings that were from the randomly selected students.

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