Answer:
An alternative definition for the acceleration ax that can be written in terms of
and
is 
Step-by-step explanation:
We know that :

Now we are supposed to find an alternative definition for the acceleration ax that can be written in terms of
and 
So, We will use chain rule over here :
![a_x=\frac{dv_x}{dt}\\a_x=\frac{dv_x}{dt} \times \frac{dx}{dx}\\a_x=\frac{dv_x}{dx} \times \frac{dx}{dt}\\a_x=\frac{dv_x}{dx} \times \frac{dx}{dt} [\frac{dx}{dt}=v_x]\\a_x=\frac{dv_x}{dx} \times v_x\\a_x=v_x\frac{dv_x}{dx}](https://tex.z-dn.net/?f=a_x%3D%5Cfrac%7Bdv_x%7D%7Bdt%7D%5C%5Ca_x%3D%5Cfrac%7Bdv_x%7D%7Bdt%7D%20%5Ctimes%20%5Cfrac%7Bdx%7D%7Bdx%7D%5C%5Ca_x%3D%5Cfrac%7Bdv_x%7D%7Bdx%7D%20%5Ctimes%20%5Cfrac%7Bdx%7D%7Bdt%7D%5C%5Ca_x%3D%5Cfrac%7Bdv_x%7D%7Bdx%7D%20%5Ctimes%20%5Cfrac%7Bdx%7D%7Bdt%7D%20%20%5B%5Cfrac%7Bdx%7D%7Bdt%7D%3Dv_x%5D%5C%5Ca_x%3D%5Cfrac%7Bdv_x%7D%7Bdx%7D%20%5Ctimes%20v_x%5C%5Ca_x%3Dv_x%5Cfrac%7Bdv_x%7D%7Bdx%7D)
Hence an alternative definition for the acceleration ax that can be written in terms of
and
is 
Answer:
Domain of piece 1:[) -4,-1
Domain of piece 2: [) -1,1
Domain of piece 3:[] 1,5
Step 2:
Rule for piece 1: y=-x
Rule for piece 2: y=1
Rule for piece 3: y=2-x
Step-by-step explanation:
Correct on Edgen
Answer:
Belinda's score is 32 strokes.
Step-by-step explanation:
Let the score of John be "x" and Belinda be "y".
It is given that, in the game of golf, John's score was 10 less than two times Belinda's score.
Also, John's score is 54 strokes.
The above equation can be written as ;

Here, x = 54,



Thus, Belinda's score is 32 strokes.
Answer:
Rational numbers are; A, E, F, I
Integers are; H and D
Whole numbers are J and B
Natural numbers is G
Please find attached the location of the letters on the real number system
Step-by-step explanation:
Rational numbers are numbers that can be expressed as the ratio, a/b, of two numbers as a/b where a and b are integers
Integers are the negative and positive whole numbers
Whole numbers are the positive counting numbers from 0 and above
Natural numbers are the positive counting numbers, sometimes including 0.
Answer:
The number of different combinations of three students that are possible is 35.
Step-by-step explanation:
Given that three out of seven students in the cafeteria line are chosen to answer a survey question.
The number of different combinations of three students that are possible is given as:
7C3 (read as 7 Combination 3)
xCy (x Combination y) is defines as
x!/(x-y)!y!
Where x! is read as x - factorial or factorial-x, and is defined as
x(x-1)(x-2)(x-3)...2×1.
Now,
7C3 = 7!/(7 - 3)!3!
= 7!/4!3!
= (7×6×5×4×3×2×1)/(4×3×2×1)(3×2×1)
= (7×6×5)/(3×2×1)
= 7×5
= 35
Therefore, the number of different combinations of three students that are possible is 35.