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Nina [5.8K]
1 year ago
15

What is the length of EF in the right triangle below?

Mathematics
2 answers:
Lyrx [107]1 year ago
8 0

Answer:

\sqrt(217)

Step-by-step explanation:

(19)^2=(12)^2

361 - 144 + 217

\sqrt(217)


andriy [413]1 year ago
8 0

Answer:

\sqrt{217}units

Step-by-step explanation:

Given : A right angled triangle EFD

           Hypotenuse = ED=19 units

           Base = DF =12 units

           Perpendicular = EF

Solution:

To find length of EF we will use Pythagorean Theorem:

(Hypotenuse)^{2}=(Perpendicular)^{2}+(Base)^{2}

ED^{2}=EF^{2}+DF^{2}

19^{2}=EF^{2}+12^{2}

361=EF^{2}+144

361-144=EF^{2}

217=EF^{2}

\sqrt{217} =EF

Thus the length of EF is \sqrt{217}units

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