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Setler79 [48]
2 years ago
10

What is the value of y? y = Find the following angle measures. mJKM = ° mMKL

Mathematics
2 answers:
shusha [124]2 years ago
8 0

Answer: ∠JKM = 106\textdegree and

 ∠JKM = 74\textdegree

Step-by-step explanation:

Since we have given that

∠JKM=10y+6

∠MKL=8y-6

Since they are linear pairs ,

So, 10y+6+8y-6=180\textdegree \\\\18y=180\textdegree \\\\y=\frac{180\textdegree}{18\textdegree}\\\\y=10\textdegree

∠JKM = 10\times 10+6=100+6=106\textdegree

and

∠MKL = 8\times 10-6=80-6=74\textdegree

tangare [24]2 years ago
3 0

<h2>y = 10°</h2><h2>∠MKL = 74°</h2><h2>∠JKM = 106°</h2>

<h3>Further explanation</h3>

Firstly , let us learn about trigonometry in mathematics.

Suppose the ΔABC is a right triangle and ∠A is 90°.

<h3>sin ∠A = opposite / hypotenuse</h3><h3>cos ∠A = adjacent / hypotenuse</h3><h3>tan ∠A = opposite / adjacent </h3>

There are several trigonometric identities that need to be recalled, i.e.

cosec ~ A = \frac{1}{sin ~ A}

sec ~ A = \frac{1}{cos ~ A}

cot ~ A = \frac{1}{tan ~ A}

tan ~ A = \frac{sin ~ A}{cos ~ A}

Let us now tackle the problem!

This problem is about Supplementary Angles.

∠MKL + ∠JKM = 180°

( 8y - 6 ) + ( 10y + 6 ) = 180°

18y = 180°

y = 180° / 18

<h2>y = 10°</h2>

<h2>∠MKL = ( 8y - 6 )° = (8 ( 10 ) - 6)° = 74°</h2><h2>∠JKM = ( 10y + 6 )° = (10 ( 10 ) + 6)° = 106°</h2>

<h3>Learn more</h3>
  • Calculate Angle in Triangle : brainly.com/question/12438587
  • Periodic Functions and Trigonometry : brainly.com/question/9718382
  • Trigonometry Formula : brainly.com/question/12668178

<h3>Answer details</h3>

Grade: College

Subject: Mathematics

Chapter: Trigonometry

Keywords: Sine , Cosine , Tangent , Opposite , Adjacent , Hypotenuse  

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The average sea level in 1900 at London bridge was 33 feet. In 1990 it was 33.08 feet. Use linear interpolation or extrapolation
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