Question

A merry-go-round has a radius of 18 feet. If a passenger gets on a

Answer 1

Answer:

The angle of rotation is 2.11 °

Step-by-step explanation:

Given as :

The radius of the round path = r = 18 feet

The length of the distance cover by wheel = l = 38 feet

Let The angle of rotation = Ф

Now, According to question

∵ length of the arc of a circle subtending an angle at center = Ф

So,

length of the distance cover by wheel = π × radius × $\frac{\Theta }{180^{\circ}}$

Since 180° = π radian

And π = 3.14

So, length of the distance cover by wheel = 180 °× radius ×  $\frac{\Theta }{180^{\circ}}$

i.e  l = r × Ф

Or,  Ф = $\frac{l}{r}$

Or,  Ф =  $\frac{38 feet}{18 feet}$

Or, Ф = 2.11 °

So, The angle of rotation =  Ф = 2.11 °

Hence, The angle of rotation is 2.11 °   Answer