Question

a six sided number cube has faces with the numbers 1 through 6 marked on them. what is the probability that a number less than 2 will occur on one toss of the number cube

Answer 1

Less than two would be one.  Since there is only one of that, it would be 1/6th or 0.6666

Answer 2

Solution:

we are given that

A six sided number cube has faces with the numbers 1 through 6 marked on them.

we have been asked to find the probability that a number less than 2 will occur on one toss of the number cube.

Since a number less than 2 is only one and that is "1" and total number of possible outcome is 6.

and as we know that probability is given using the formula

$P(E)= \frac{n(E)}{n(S)}$

Substitute the values we get

$P(E)= \frac{1}{6}$

Hence the required probability is 1/6.