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Aleks [24]
2 years ago
14

Hariette would like to review the income and expenses that were actually paid last month so she can determine how much to set as

ide for her estimated taxes. What accounting method should Hariette choose when she runs the Profit & Loss report? Cash (basis) Accrual (basis) Modified (basis) Hybrid (basis)
Mathematics
1 answer:
Brrunno [24]2 years ago
5 0

Answer:

Hybrid basis

Step-by-step explanation:

There are different methods of accounting used by businesses depending on their peculiar needs. Below are the type of accounting methods:

- Cash basis is when revenues and expenses are recognised when cash is recieved or paid out.

-Accrual basis is when revenue and expenses are recognised when they are earned. For example if services are rendered to a client that will pay in a week's time, since service has already been given it is considered that the future payment has been earned.

- Modified basis combines elements of cash and accrual basis. For example considering short term assets like accounts receivable and accounts payable as cash items. Long term assets are recorded on accrual basis.

- Hybrid basis is used when cash and accrual methods are used for various expenses and tax. Mostly it is used for internal accounting purposes.

In this scenario Hariette would like to review the income and expenses that were actually paid last month. This requires a cash basis that shows actual amount recieved and paid last month. Account receivable and payable are not considered.

In setting aside money for tax she will employ accrual basis accounting. It is an expense that is estimated for future use.

So the hybrid basis is the method that will be most suitable.

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Swati wants to distribute sweets to some of her friends.
krek1111 [17]

Answer:47

Step-by-step explanation:

14+15+10+8=47

8 0
2 years ago
Gina sold 5/8 of a mushroom pizza and 3/4 of an onion pizza to the same family.How much pizza in all did the family buy?
Murrr4er [49]

Answer:

1 and 3/8 of pizza

Step-by-step explanation:

5/8 + 3/4

3/4 x 2 to get the same denominator as 5/8

5/8 + 6/8 = 11/8

11/8 = 1 3/8

6 0
2 years ago
The rabbit population on a small island is observed to be given by the function P(t) = 130t − 0.3t^4 + 1100 where t is the time
Montano1993 [528]
The maximum occurs when the derivative of the function is equal to zero.
P(t)=-0.3t^{4}+130t+1100 \\ P'(t)=-1.2t^{3}+130 \\ 0=-1.2t^{3}+130 \\ 1.2t^{3}=130 \\ t^{3}= \frac{325}{3}  \\ t=4.76702
Then evaluate the function for that time to find the maximum population.
P(t)=-0.3t^{4}+130t \\ P(4.76702)=-0.3*4.76702^{4}+130*4.76702+1100 \\ P(4.76702)=1564.79201
Depending on the teacher, the "correct" answer will either be the exact decimal answer or the greatest integer of that value since you cannot have part of a rabbit.
7 0
2 years ago
Below is the five Number summary for a 136 hikers who recently completed the John muir trail JMT the variable is the amount of t
Helga [31]

Answer:

IQR = Q_3 -Q_1 = 28-18 = 10

Now we can find the limits in order to determine outliers like this:

Left = Q_1 -1.5 IQR = 18 -1.5*10=3

Right = Q_1 +1.5 IQR = 18 +1.5*10=33

So for this case the left boundary would be 3, if a value is lower than 3 we consider this observation as an outlier

b. 3

Step-by-step explanation:

For this case we have the following summary:

Minimum = 9 represent the minimum value

Q_1 = 18 represent the first quartile

Median =Q_2= 21 represent the median

Q_3 = 28 represent the third quartil

Maximum=56 represent the maximum

If we use the 1.5 IQR we need to find first the interquartile range defined as:

IQR = Q_3 -Q_1 = 28-18 = 10

Now we can find the limits in order to determine outliers like this:

Left = Q_1 -1.5 IQR = 18 -1.5*10=3

Right = Q_1 +1.5 IQR = 18 +1.5*10=33

So for this case the left boundary would be 3, if a value is lower than 3 we consider this observation as an outlier

b. 3

7 0
2 years ago
The average diameter of sand dollars on a certain island is 5.00 centimeters with a standard deviation of 0.90 centimeters. If 1
Montano1993 [528]

Answer:

the probability that the average diameter of those sand dollars is more than 4.73 centimeters is 0.5910

Step-by-step explanation:

Given information:

mean, x = 5

standard deviation, σ = 0.9

number of sample, n = 16

now we calculate the probability that the average diameter of those sand dollars is more than 4.73 centimeters.

P(x>4.73)  = P (z > (4.73 - x) / (σ \sqrt{n})

                = P (z > (4.73 - 4) / (0.9 \sqrt{16})

                = P (z > 0.203)

                = 0.5910

4 0
2 years ago
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