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Hoochie [10]
1 year ago
9

Use the scale and map measurements to find the actual distance from New Wilmington to Sharon through Mercer. What is the actual

distance if you travel from New Wilmington to Sharon through Volant?
51 mi; 45 mi

102 mi; 90 mi

76.5 mi; 67.5 mi

25.5 mi; 22.5 mi

Mathematics
2 answers:
Fynjy0 [20]1 year ago
8 0
Your answer is C!

Hope i helped!
  

~Cakes



irga5000 [103]1 year ago
6 0

Answer:

Option A. 51miles, 45 miles

Step-by-step explanation:

Distance between New Wellington to Sharon through Mercer is given as

Distance between New Wellington to Mercer + Distance between Mercer to Sharon

= 2 + 2.25

= 4.25 in.

Now we have been given the conversion formula as

1 in = 12 miles

So 4.25 in. will be = 12×4.25 miles

                              = 51 miles

Therefore, actual distance from New Wilmington to Sharon via Mercer is 51 miles.

Now we have to calculate the actual distance between New Wilmington to Sharon through Volant.

Distance between New Wilmington to Volant = 1 in.

and distance between Volant to Sharon = 2.75 in.

Distance between New Wilmington to Sharon via Sharon = 2.75 + 1 = 3.75 in.

Now we will use conversion table to get the actual distance.

∵ 1 in. distance = 12 miles

∴ 3.75 in distance = 12×3.75 = 45 miles

Therefore, Option A. 51 miles and 45 miles is the answer.

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Which graph best represents the following situation? As x increases, y decreases; r=-0.87.
liberstina [14]

Answer:

Graph A.

Step-by-step explanation:

The X-Axis refers to strictly horizontal movement, so the farther right it moves, the lower the dots should be on the graph because (x+,y-).

8 0
2 years ago
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Omar and Caleb each had a repair made on their cars. The initial cost of each repair is $1,000. Omar and
nataly862011 [7]

Answer:

Caleb paid less than Omar by $12.

Step-by-step explanation:

The initial cost of each repair is $1,000.

One  coupon is for $80 off the repair cost. The other coupon is for 15% off the repair cost.

Case 1:

Omar uses the $80 off the repair cost coupon first. He then uses the 15% off the repair cost coupon on  the remaining balance.

Step 1: 1000-80=920

Step 2: 920-(0.15\times920)=782 dollars

Case 2:

Caleb uses the 15% off the repair cost coupon first. He then uses the $80 off the repair cost coupon on  the remaining balance.

Step 1: 1000-(0.15\times1000)=850

Step 2: 850-80=770 dollars

Now, comparing the values we can see that Caleb paid less.

He paid less by 782-770=12 dollars.

8 0
1 year ago
Find the inverse of y=x2-10x
anzhelika [568]
<span>this is pretty hard but here is your answer 
</span>

y = x^2 - 10x + 25 - 25

<span> y = (x-5)^2 - 25 </span>

<span> y+25 = (x-5)^2 </span>

<span> x-5 = +/-sqrt(y+25) </span>

 

<span> And you get TWO inverses: </span>

 

<span> x = 5 + sqrt(y+25), for x>=5 </span>

<span> x = 5 - sqrt(y+25), for x<=5</span>


5 0
2 years ago
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Which ordered pairs are solutions to the inequality 2y−x≤−6 ?
Vinil7 [7]
Given inequality: 2y−x ≤ −6

Option-1 : (-3,0)
2×0 - (-3) = 0 + 3 = 3 > -6
Not satisfied

Option-2 : (6,1)
2×1 - 6 = 2 - 6 = -4 > -6
Not satisfied

Option-3 : (1, -4)
2×(-4) - 1 = -8 - 1 = -9 < -6
Satisfied.
Thus, (1, -4) is a solution.

Option-4 : (0, -3)
2×(-3) - 0 = -6 - 0 = -6 = -6
Satisfied.
Thus, (0, -3) is a solution.

Option-5 : (2, -2)
2×(-2) - 2 = -4 - 2 = -6 = -6
Satisfied.
Thus, (2, -2) is a solution.

Solutions are: (1, -4), (0, -3) , (2, -2)

4 0
1 year ago
Alice has a 4-inch by 5-inch photo of your school’s championship girls’ ice hockey team. To celebrate their recent
Pachacha [2.7K]

Alice should pick the enlarged-photo with dimensions of 8-inch by 10-inch.

Step-by-step explanation:

Step 1:

In order for a part of the photo to not be cut off, the enlarged photo's dimensions should be of a constant ratio with the original photo's dimensions.

We divide the dimensions of the enlarged-photo with the dimensions of the original photo to check which has a constant ratio.

Step 2:

The original photo was a 4-inch by 5-inch photo.

Option 1 is 7-inch by 9-inch, so the ratios are

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Option 2 is 8-inch by 10-inch, so the ratios are

\frac{8}{4} = 2, \frac{10}{5} = 2. The ratios are the same so this can be the enlarged photo's dimensions.

Option 3 is 12-inch by 16-inch, so the ratios are

\frac{12}{4} = 3, \frac{16}{5} = 3.2. The ratios are different so this cannot be the enlarged photo's dimensions.

So the enlarged-photo with dimensions of 8-inch by 10-inch should be picked.

7 0
2 years ago
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