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choli [55]
2 years ago
5

Suppose F⃗ (x,y)=⟨ex,ey⟩F→(x,y)=⟨ex,ey⟩ and CC is the portion of the ellipse centered at the origin from the point (0,1)(0,1) to

the point (7,0)(7,0) centered at the origin oriented clockwise. (a) Find a vector parametric equation r⃗ (t)r→(t) for the portion of the ellipse described above for 0≤t≤π/20≤t≤π/2.
Mathematics
1 answer:
Rudik [331]2 years ago
7 0

Probably the intended ellipse is the one with equation

\dfrac{x^2}{49}+y^2=1

We can parameterize C as a piece of this curve by

\vec r(t)=\langle7\sin t,\cos t\rangle

with 0\le t\le\frac\pi2. Then

\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\int_0^{\pi/2}\langle e^{7\sin t},e^{\cos t}\rangle\cdot\langle7\cos t,-\sin t\rangle\,\mathrm dt

etc

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Let P and Q be polynomials with positive coefficients. Consider the limit below. lim x→[infinity] P(x) Q(x) (a) Find the limit i
jenyasd209 [6]

Answer:

If the limit that you want to find is \lim_{x\to \infty}\dfrac{P(x)}{Q(x)} then you can use the following proof.

Step-by-step explanation:

Let P(x)=a_{n}x^{n}+a_{n-1}x^{n-1}+\cdots+a_{1}x+a_{0} and Q(x)=b_{m}x^{m}+b_{m-1}x^{n-1}+\cdots+b_{1}x+b_{0} be the given polinomials. Then

\dfrac{P(x)}{Q(x)}=\dfrac{x^{n}(a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)}+a_{0}x^{-n})}{x^{m}(b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m})}=x^{n-m}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)})+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}

Observe that

\lim_{x\to \infty}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)})+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}=\dfrac{a_{n}}{b_{m}}

and

\lim_{x\to \infty} x^{n-m}=\begin{cases}0& \text{if}\,\, nm\end{cases}

Then

\lim_{x\to \infty}=\lim_{x\to \infty}x^{n-m}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)}+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}=\begin{cases}0 & \text{if}\,\, nm \end{cases}

3 0
2 years ago
The volumes of two similar figures are 343 mm3 and 512 mm3. If the surface area of the larger figure is 192 mm2, what is the sur
Kobotan [32]
In geometry, similar figures are those whose ratios of the  corresponding sides are equal and the corresponding  angles are congruent. In relation to the volume, we determine first the cube roots of the given and find the ratio as shown below.
 
                         s1 / s2 = cube root of (512/343)
                                    = 8/7
The square of this ratio is the ratio of the areas of the figure. If we let x be the area of the smaller figure then, 
                      (8/7)^2 = 192 mm²/ x
The value of x from the equation is 147 mm². 

The area therefore of the smaller figure is 147 mm².
3 0
2 years ago
Read 2 more answers
Need help asap. Consider the diagram.
fgiga [73]

ANSWER

<em>alternate interior angles theorem</em>

EXPLANATION

According to the alternate interior angles theorem, when two parallel lines are are intercepted by a straight line (transversal) the angles in the interior corners of a Z-shape pattern are congruent.

From the above diagram line r is parallel to line s, therefore

\angle \: 3 \cong \angle6

and

\angle \: 4\cong \angle5

because they are alternate interior angles.

See attachment for how to spot alternate interior angles.

5 0
2 years ago
Read 2 more answers
A local project being analyzed by PERT has 42​ activities, 13 of which are on the critical path. If the estimated time along the
ryzh [129]

Answer:

the probability that the project will be completed in 95 days or​ less, P(x ≤ 95) = 0.023

Step-by-step explanation:

This is a normal probability distribution question.

We'll need to standardize the 95 days to solve this.

The standardized score is the value minus the mean then divided by the standard deviation.

z = (x - xbar)/σ

x = 95 days

xbar = mean = 105 days

σ = standard deviation = √(variance) = √25 = 5

z = (95 - 105)/5 = - 2

To determine the probability that the project will be completed in 95 days or​ less, P(x ≤ 95) = P(z ≤ (-2))

We'll use data from the normal probability table for these probabilities

P(x ≤ 95) = P(z ≤ (-2)) = 0.02275 = 0.023

5 0
2 years ago
A store sells T-shirts for $10 each and jeans for $20 a pair. Anna spends $150 on T-shirts and jeans. She buys x T-shirts and y
Natalija [7]
The equation is 10x+20y=150 
7 0
2 years ago
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