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vladimir2022 [97]
2 years ago
10

How does the saying "money breeds money" apply to simple interest?

Mathematics
2 answers:
r-ruslan [8.4K]2 years ago
6 0
It applies because interest slowly increases the amount of money gained. IF you have any Tolkien related questions, feel free to ask me

horsena [70]2 years ago
6 0

The simple interest is calculated as the principle amount times the rate of interest times the number of years.

So, if our principle amount is $100 and rate is 5% and time is 1 year, then at the end of the year we will yield an interest of :

100\times0.05\times1=5 Hence, we will earn $5 over our initial amount of $100 making it $105 by the end of one year. Then next year again, we will get, 105\times0.05\times1=5.25 making it 105+5.25=110.25 by second year end and this chain continues.

In this way we can see that each year the initial amount is increasing with simple interest. So, this validates the sentence 'money breeds money' .

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Math 1314 lab module 2
denpristay [2]
What, is there a question or no?
8 0
2 years ago
PLEASE ANSWER FAST!!!!
xz_007 [3.2K]

Answer:

The answer is 24.

Step-by-step explanation:

5 0
2 years ago
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6 points Emily’s family needs to rent a moving truck to move their belongings to a different house. The rental cost for Trucks-A
Alexxx [7]

Answer/Step-by-step explanation:

Equation to represent the daily rental cost for each type of truck can be written as follows:

Daily rental cost for Trucks-A-Lot = 42 + 0.72m

Daily rental cost for Move-in-Truckers = 70 + 0.12m

Where, m = Emily's mileage

To determine the number of miles for which the truck cost the same amount, set both equations equal to each other and solve for m.

42 + 0.72m = 70 + 0.12m

Collect like terms

0.72m - 0.12m = 70 - 42

0.6m = 28

Divide both sides by 0.6

\frac{0.6m}{0.6} = \frac{28}{0.6}

m = 46.7

At approximately 47 miles, both trucks would cost the same amount.

Check:

Daily rental cost for Trucks-A-Lot = 42 + 0.72m

Plug in the value of x = 47

= 42 + 0.72(47) = $75.84 ≈ $76

Daily rental cost for Move-in-Truckers = 70 + 0.12m

Plug in the value of x = 47

= 70 + 0.12(47) = $75.64 ≈ $76

7 0
2 years ago
Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).
lord [1]

Given : A florist currently makes a profit of $20 on each of her celebration bouquets and sells an average of 30 bouquets every week . and graph

To Find :  Maximum profit , breakeven point , profit interval

Solution:

The maximum profit the florist will earn from selling celebration bouquets is $ 675

peak of y from Graph

The florist will break-even after  Selling 20     one-dollar decreases.

at breakeven

Break even is the point where the profit p(x) becomes 0

The interval of the number of one-dollar decreases for which the florist makes a profit from celebration bouquets is (0 ,20).

after 20 , P(x) is - ve

3 0
2 years ago
Read 2 more answers
Which of the following represents the zeros of f(x) = 5x3 − 6x2 − 59x + 12? (2 points)
Furkat [3]

Answer:

4, −3, 1 over 5

Step-by-step explanation:

x is a zero of f(x) if f(x) = 0

In this problem, we have that:

f(x) = 5x^{3} - 6x^{2} - 59x + 12

4, 3, 1 over 5

f(4) = 5*4^{3} - 6*4^{2} - 59*4 + 12 = 0

So 4 is a zero of the function

f(3) = 5*3^{3} - 6*3^{2} - 59*3 + 12 = -84

So 3 is not a zero of the function, and this option is incorrect

4, 3, − 1 over 5

f(3) = 5*3^{3} - 6*3^{2} - 59*3 + 12 = -84

So 3 is not a zero of the function, and this option is incorrect

4, −3, 1 over 5

f(4) = 5*4^{3} - 6*4^{2} - 59*4 + 12 = 0

So 4 is a zero of the function

f(-3) = 5*(-3)^{3} - 6*(-3)^{2} - 59*(-3) + 12 = 0

So -3 is a zero of the function

f(\frac{1}{5}) = f(0.2) = 5*(0.2)^{3} - 6*(0.2)^{2} - 59*(0.2) + 12 = 0

So 1 over 5 is a zero of the function

This is the correct answer.

4, −3, −1 over 5

f(4) = 5*4^{3} - 6*4^{2} - 59*4 + 12 = 0

So 4 is a zero of the function

f(-3) = 5*(-3)^{3} - 6*(-3)^{2} - 59*(-3) + 12 = 0

So -3 is a zero of the function

f(-\frac{1}{5}) = f(-0.2) = 5*(-0.2)^{3} - 6*(-0.2)^{2} - 59*(-0.2) + 12 = 23.52

-1 over 5 is not a zero of the function

5 0
2 years ago
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