Question

What is the slope-intercept form of the following equation? 10x + 4y = 16 options: a.) y =−5/2x + 16 b.) y = −5/2x + 4 c.) 4y =−10x + 16 d.) y = −10x + 16

Answer 1

Answer:

$y=-\frac{5}{2}x+4$

Step-by-step explanation:

we know that

The equation of the line in slope intercept form is equal to

$y=mx+b$

where

m is the slope

b is the y-intercept

we have

$10x+4y=16$

Solve for y

That means -----> isolate the variable y

Subtract 10x both sides

$4y=16-10x$

Divide by 4 both sides

$y=(16-10x)/4$

Simplify

$y=4-\frac{5}{2}x$

Rewrite

$y=-\frac{5}{2}x+4$

Answer 2

Answer:

The answer is option (b), y=-5/2x+4

Step-by-step explanation:

The slope intercept form is a way of expressing the equation of a straight line;  where there are two variables that vary in a linear form. The equation is always of the form; y=mx+c

Where;

• y and x represents the variables on the y and x axis respectively
• m is a real number representing the slope
• c is also a real number representing the y-co-ordinate, where the line intercepts the y-axis

Solving for y in 10x+4y=16

(4y)/4=(-10x)/4+(16/4)

The answer is y=-5/2x+4, option (b)