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Eva8 [605]
2 years ago
13

A cube with side length 2f is stacked on another cube with side length 3g2. Choose the expression that represents the total volu

me of the cubes.
Mathematics
2 answers:
Reil [10]2 years ago
4 0
The expression that represents the total volume of both cubes is 8f^3+27g^6.

The volume of a cube is found by multiplying its length, width, and height; for the first cube, this is 
V=(2f)(2f)(2f)=8f³.

For the second cube, this is
V=(3g²)(3g²)(3g²)=27g⁶.

The total area is their sum, so 8f³+27g⁶.
Damm [24]2 years ago
3 0

Answer:

the answer is c

Step-by-step explanation:


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To make lemonade, you used one quart of water, one pint of lemon juice, and 9 ounces of your secret ingredient: honey. How much
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To solve this problem you must follow the proccedure shown below:

 1. Amount of lemonade in pints:

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 Total in pints=2 pints+1 pint+0.56 pints
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4 0
2 years ago
An ant begins at the top of the pictured octahedron. If the ant takes two "steps", what is the probability it ends up at the bot
Aleksandr-060686 [28]

Answer:

P_{bottom}=\frac{1}{4}=0.25

Step-by-step explanation:

Starting from the top, the ant can only take four different directions, all of them going down, every direction has a probability of 1/4. For the second step, regardless of what direction the ant walked, it has 4 directions: going back (or up), to the sides (left or right) and down. If the probability of the first step is 1/4 for each direction and once the ant has moved one step, there are 4 directions with the same probability (1/4  again), the probability of taking a specific path is the multiplication of the probability of these two steps:

P_{2steps}=\frac{1}{4}*\frac{1}{4}=\frac{1}{16}

There are only 4 roads that can take the ant to the bottom in 2 steps, each road with a probability of 1/16, adding the probability of these 4 roads:

P_{bottom}=\frac{1}{16}+\frac{1}{16}+\frac{1}{16}+\frac{1}{16}=\frac{4}{16}=\frac{1}{4}

The probability of the ant ending up at the bottom is \frac{1}{4} or 0.25.

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Answer: 21

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The answer to the question is a
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