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pshichka [43]
2 years ago
13

Describe the general properties of rotations. Include a discussion of the properties of rigid transformations, and line segments

connecting corresponding points to each other and to the center of rotation.
Mathematics
2 answers:
Alex777 [14]2 years ago
4 0

Sample Response: Rotations are rigid transformations, which means they preserve the size, length, shape, and angle measures of the figure. However, the orientation is not preserved. Line segments connecting the center of rotation to a point on the pre-image and the corresponding point on the image have equal length. The line segments connecting corresponding vertices are not parallel.


Yanka [14]2 years ago
4 0

Answer:

Sample Response: Rotations are rigid transformations, which means they preserve the size, length, shape, and angle measures of the figure. However, the orientation is not preserved. Line segments connecting the center of rotation to a point on the pre-image and the corresponding point on the image have equal length. The line segments connecting corresponding vertices are not parallel.

Step-by-step explanation:

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A box can hold a maximum of 8 cans. You have 50 cans to put in boxes. What is the smallest number of boxes you need to store all
xeze [42]

Answer:

7boxes

Step-by-step explanation:

A box can hold a maximum of 8 cans

You have a total of 50 cans

The problem here is to determine the minimum number of boxes that can hold the 50 cans

Let the minimum number of boxes = y

The minimum required will be such that:

The Product of The number of cans X Number of Required boxes ≥50

8y≥50

y≥50/8

y≥6.25

Since a box have a fractional value, the minimum number of boxes required to store 50 cans will be the nearest whole number which in this case is 7.

3 0
2 years ago
(n) ________ is a variable that affects both variables of interest and may falsely give the impression of a cause-and-effect rel
gtnhenbr [62]

Answer: CONFOUNDING VARIABLES

Step-by-step explanation: Confounding variables are

unexpected external factor that affects both variables of interest, confounding variables usually gives the false impression that changes in one variable leads to changes in the other variable, when, in Actual, it is the external factor that caused the change being investigated. Confounding variables usually leads to wrong conclusions during research and experiments and are capable of causing biased outcomes when the real cause and effect relationship is not determined.

4 0
2 years ago
J.J.Bean sells a wide variety of outdoor equipment and clothing. The company sells both through mail order and via the internet.
melamori03 [73]

Answer:

99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

Step-by-step explanation:

We are given that a random sample of 16 sales receipts for mail-order sales results in a mean sale amount of $74.50 with a standard deviation of $17.25.

A random sample of 9 sales receipts for internet sales results in a mean sale amount of $84.40 with a standard deviation of $21.25.

The pivotal quantity that will be used for constructing 99% confidence interval for true mean difference is given by;

                      P.Q.  =  \frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }  ~ t__n_1_+_n_2_-_2

where, \bar X_1 = sample mean for mail-order sales = $74.50

\bar X_2 = sample mean for internet sales = $84.40

s_1 = sample standard deviation for mail-order purchases = $17.25

s_2 = sample standard deviation for internet purchases = $21.25

n_1 = sample of sales receipts for mail-order purchases = 16

n_2 = sample of sales receipts for internet purchases = 9

Also,  s_p =\sqrt{\frac{(n_1-1)\times s_1^{2}+(n_2-1)\times s_2^{2} }{n_1+n_2-2} }  =  \sqrt{\frac{(16-1)\times 17.25^{2}+(9-1)\times 21.25^{2} }{16+9-2} } = 18.74

The true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is represented by (\mu_1-\mu_2).

Now, 99% confidence interval for (\mu_1-\mu_2) is given by;

             = (\bar X_1-\bar X_2) \pm t_(_\frac{\alpha}{2}_)  \times s_p \times \sqrt{\frac{1}{n_1} +\frac{1}{n_2}}

Here, the critical value of t at 0.5% level of significance and 23 degrees of freedom is given as 2.807.

          = (74.50-84.40) \pm (2.807  \times 18.74 \times \sqrt{\frac{1}{16} +\frac{1}{9}})

          = [$-31.82 , $12.02]

Hence, 99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

5 0
2 years ago
Select all that apply. To decide if 12.5 centimeters is greater than 140 millimeters, the first step is to set up a proportion.
Oksi-84 [34.3K]

Answer:

Hey there!

We can't compare two measurements without converting them to  the same units. Thus, we use proportions to make all the values into the same unit.

12.5 cm(\frac{10 milimeters}{1 centimeter}), which converts to centimetres to millimetres.

12.5 cm=125 mm.

Now, we can compare the values of 125 mm and 140 mm.

Clearly, we see that 140 mm is greater than 125 mm.

Let me know if this helps :)

3 0
2 years ago
Read 2 more answers
Tiffany buys a basket of watermelons on sale for \$9$9dollar sign, 9 before tax. The sales tax is 9\%9%9, percent. What is the t
vladimir2022 [97]
Given that the basket of watermelons sells for $9 before tax and the tax rate is 9%.

The tax on the basket of watermelons is given by

\frac{9\%}{100\%} \times\$9=0.09\times\$9 \\  \\ =\$0.81

Therefore, the total price Tiffany pays for the basket of watermelons is $9 + $0.81 = $9.81
8 0
2 years ago
Read 3 more answers
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