Answer:

Step-by-step explanation:
We are given the following in the question:
We treat adult having blood type A as a success.
P(Blood type A) =

Then the number of Children of Juan and Maria who have blood type A follows a binomial distribution as there are
- n independent trial.
- Each trial have to outcomes(Blood type A or not)
- Probability of success is same for each success
Here,
where n is the total number of observations, x is the number of success, p is the probability of success.
Thus, for the given binomial distribution,

I looked at another online and it said letter A. (Not 100% sure)
Answer:
Billy’s angular velocity, is 1508.16 radians per second
Step-by-step explanation:
We have to find angular velocity in radians per second
we have given angular velocity w = 4 revolutions per minute
we have to convert revolutions into radians and minutes into seconds.
so, we use the following conversion:
1 rev = 2* pi radians (where pi = 22/7 or 3.142)
1 min = 60 sec
putting the values in our equation : w = 4 revolutions per minute
=> w= 4 * ( 2* 3.142) *60
=> w= 1508.16 radians per second
hence Billy’s angular velocity, is 1508.16 radians per second
Answer:
There is no significant evidence which shows that there is a difference in the driving ability of students from West University and East University, <em>assuming a significance level 0.1</em>
Step-by-step explanation:
Let p1 be the proportion of West University students who involved in a car accident within the past year
Let p2 be the proportion of East University students who involved in a car accident within the past year
Then
p1=p2
p1≠p2
The formula for the test statistic is given as:
z=
where
- p1 is the <em>sample</em> proportion of West University students who involved in a car accident within the past year (0.15)
- p2 is the <em>sample</em> proportion of East University students who involved in a car accident within the past year (0.12)
- p is the pool proportion of p1 and p2 (
) - n1 is the sample size of the students from West University (100)
- n2 is the sample size ofthe students from East University (100)
Then we have z=
≈ 0.6208
Since this is a two tailed test, corresponding p-value for the test statistic is ≈ 0.5347.
<em>Assuming significance level 0.1</em>, The result is not significant since 0.5347>0.1. Therefore we fail to reject the null hypothesis at 0.1 significance