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Vanyuwa [196]
2 years ago
14

If it takes 10 seconds for 10 printers to print out 10 pages of paper, how many seconds will it take 50 printers to print out 50

pages of paper?
Mathematics
2 answers:
SSSSS [86.1K]2 years ago
8 0
We know that 10 printers print 10 pages of paper for 10 seconds.
In order to calculate how many seconds are needed for 50 printers to print out 50 pages  of paper -denoted with X, we should compare these situation with the situation we know (10 printers print 10 pages).
The number of printers is 5 times bigger and the number of pages is also 5 times bigger, which means we can write:
X=5*(seconds needed <span>10 printers to print 10 pages)
X=5*10seconds
X=50 seconds
</span><span>It takes 50 seconds for 50 printers to print out 50 pages of paper.</span>
Fed [463]2 years ago
4 0

Lets use the formula RWT=J to solve this, where,

  • R is the rate
  • W is the number of workers/things
  • T is time
  • J is number of jobs/things

<em><u>"If it takes 10 seconds for 10 printers to print out 10 pages of paper"</u></em> - here -

W is 10 printers, T is 10 seconds,  and J is 10 pages. We can write:

R(10)(10)=10\\R(100)=10\\R=\frac{10}{100}\\R=0.1


<u><em>"how many seconds will it take 50 printers to print out 50 pages of paper"</em></u><em> - here we use R=0.1 (previously found) to figure out T.</em>

<em>RWT=J\\(0.1)(50)T=50\\5T=50\\T=\frac{50}{5}\\T=10</em>

So it will take 10 seconds for 50 printers to print 50 pages.


ANSWER: 10 seconds

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6 questions = 30 points someone please help me
eduard

Answer:

1)D

2)D

3)A

4)B

5)Cannot Answer - No data

6)C

7)C

6 Questions answered for 30 points.

Step-by-step explanation:

Answer for the 1st Question,

Area of a cylinder can be calculated by,

Area of the cylindrical part = 2\pi rL

Area of the parts that cover the open parts of cylinder = 2\pi r^2

Therefor Total are of the cylinder = 2\pi rL+2\pi r^2

Area of the total cylinder = 2*3.14*6.8*14.2+2*3.14*6.8^2

                                          =896.784

<u>Therefor best estimate will be D) 923 in^2</u>


Answer for the 2nd Question,

ABC is a triangle.

By Pythagorean theorem it says,

(AC)^2+(CB)^2=(AB)^2

The distance from A to C = 6

The distance from C to B = 5

(AC)^2=6^2=36

(CB)^2=5^2=25

(AC)^2+(CB)^2=(AB)^2=36+25=61

Therefor (AB)^2=61\\(AB)=\sqrt{61}

<u>Therefor Answer is D) Sqr 61</u>

Answer to Question 3

To find the trend you can draw an imaginary line that fits the scatter plots.(I have attached a image drawing the imaginary lines)

Then the revenue can be calculated by calculating the area covered by the imaginary line drawn or area "under" the curve.

Area of the Store 1 =\frac{1}{2} *(110+40)*110=8250

Area of the Store 2=\frac{1}{2} *110*80=4400

Therefore Revenue from Store 1 = $8250

                 Revenue from Store 2 = $4400

<u>Answer is A) Store 1  has more sales revenue</u>

Answer for Question 4

\frac{5}{12}=0.4167\\\frac{5}{11}=0.4545

You can straight away discard answer D because it is less than both 5/12 and 5/11.

Also you can discard Answer C because 25/264 is very small (less than 1/10=0.1)

\frac{11}{23} =0.4782, therefor this is not in between those two numbers.

Then it has to be \frac{115}{264} =0.4356

<u>Answer is B)</u>


Answer for question 6

The equation of a straight line is of the form y=mx+c

here m is the gradient and c is the intercept.

Find the intercept(c) by finding the y value when x value is 0, here it is +1.

Gradient (m) of the graph can be found by,

\frac{y1-y2}{x1-x2} =\frac{7-3}{3-1} =2

Therefor the equation of the graph is,

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<u>Answer is C</u>

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\frac{7}{8} =0.875

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