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pshichka [43]
2 years ago
15

You invested a total of $12,000 at 4.5 percent and 5 percent simple interest. During one year, the two accounts earned $570. How

much did you invest in each account?
Mathematics
1 answer:
Luda [366]2 years ago
6 0

Answer: You invested $6000 in both accounts.

Step-by-step explanation:

Let x represent the amount invested in the account earning 4.5% interest.

Let y represent the amount invested in the account earning 5% interest.

You invested a total of $12,000 at 4.5 percent and 5 percent simple interest. This means that

x + y = 12000

The formula for simple interest is expressed as

I = PRT/100

Where

P represents the principal

R represents interest rate

T represents time in years

I = interest after t years

Considering the account earning 4.5%

I = (x × 4.5 × 1)/100 = 0.045x

Considering the account earning 5%

I = (y × 5 × 1)/100 = 0.05y

During one year, the two accounts earned $570. . This means that

0.045x + 0.05y = 570 - - - - - - - - - - 1

Substituting x = 12000 - y into equation 1, it becomes

0.045(12000 - y) + 0.05y = 570

540 - 0.045y + 0.05y = 570

- 0.045y + 0.05y = 570 - 540

0.005y = 30

y = 30/0.005 = 6000

x = 12000 - y = 12000 - 6000

x = $6000

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Answer:

0

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a= 20-20/ 10s

a=0m/s

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The data set below represents the total number of touchdowns a quarterback threw each season for 10 seasons of play.
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Here are your measures of variability. The range is found by subtracting the highest and the lowest (29-5=24). To find the interquartile range, you will find the median of the lower half of the data and the median of the higher half of sta and subtract these 2 numbers. Here is your list. I have PUT PARENTHESES around the upper and lower quartiles: 5, 17, (18), 20, 20, 21, 23, (26), 28, 29. It is like finding the middle of the entire set of data and then finding the middle of each half. Subtract 26 and 18 to find the interquartile range of 8 touchdowns.
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2 years ago
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Find the percent of change if the original price is $246.95 and the new price is $199.95. Round to nearest tenth of a percent if
Grace [21]

Answer:

<h3>Percentage change = 19%</h3>

Step-by-step explanation:

Since the new price is lesser than the original price the percentage change will be a decrease.

To find the percentage change use the formula

Percentage  \:  \: change =  \frac{change}{original  \:  \: quantity}  \times 100

To find the change subtract the new price from the original price

new price = $199.95

original price = $246.95

Change = $246.95 - $ 199.95 = $47

Percentage  \:  \: change =  \frac{47}{246.95}  \times 100

<h3>Percentage change = 19%</h3>

Hope this helps you

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What other points are on the line of direct variation through (5, 12)? Check all that apply. (0, 0) (2.5, 6) (3, 10) (7.5, 18) (
aalyn [17]

we know that

A relationship between two variables, x, and y, represent a direct variation if it can be expressed in the form y/x=k or y=kx

in this problem we have

the point (5,12) is on the line of direct variation

so

Find the constant of proportionality k

y/x=k-------> substitute ------> k=12/5

the equation is

y=\frac{12}{5}x

Remember that

If a point is on the line of direct variation

then

the point must satisfy the equation of direct variation

we're proceeding to verify each point

<u>case A)</u> point (0,0)

x=0\ y=0

Substitute the value of x and y in the direct variation equation

0=\frac{12}{5}*0

0=0 -------> is true

therefore

the point (0,0) is on the line of direct variation

<u>case B)</u> point (2.5,6)

x=2.5\ y=6

Substitute the value of x and y in the direct variation equation

6=\frac{12}{5}*2.5

6=6 -------> is true

therefore

the point (2.5,6) is on the line of direct variation

<u>case C)</u> point (3,10)

x=3\ y=10

Substitute the value of x and y in the direct variation equation

10=\frac{12}{5}*3

10=7.2 -------> is not  true

therefore

the point (3,10) is not on the line of direct variation

<u>case D)</u> point (7.5,18)

x=7.5\ y=18

Substitute the value of x and y in the direct variation equation

18=\frac{12}{5}*7.5

18=18 -------> is true

therefore

the point (7.5,18) is on the line of direct variation

<u>case E)</u> point (12.5,24)

x=12.5\ y=24

Substitute the value of x and y in the direct variation equation

24=\frac{12}{5}*12.5

18=30 -------> is not true

therefore

the point  (12.5,24) is not on the line of direct variation

<u>case F)</u> point (15,36)

x=15\ y=36

Substitute the value of x and y in the direct variation equation

36=\frac{12}{5}*15

36=36 -------> is true

therefore

the point (15,36) is on the line of direct variation

therefore

<u>the answer is</u>

(0,0)

(2.5,6)

(7.5,18)

(15,36)


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