Answer:
y = 22.5 - 0.2t
Step-by-step explanation:
Given;
total number of candle, n = 22.5 ounce
Rate of candle burn, R = 1 ounce per 5 hours 
The amount of candle left = total initial value - amount burnt
let the amount let = y
y = 22.5 - 0.2t
where;
t is the time in which the candle is burnt
Thus, the equation for the amount of candle left is given by;
y = 22.5 - 0.2t
we will find number of non-zero elements on each rows
and then we add them
First row:
we can see that non-zero elements are
2 , 3.1 , 22 , 9
so, number of non-zero elements in first row =4
Second row:
we can see that non-zero elements are
21 , 3.2 , 6
so, number of non-zero elements in first row =3
Third row:
we can see that non-zero elements are
1 , 42 , 8
so, number of non-zero elements in first row =3
Fourth row:
we can see that non-zero elements are
40 ,4 , 6,14
so, number of non-zero elements in first row =4
Fifth row:
we can see that non-zero elements are
10 , 20 , 13 , 5 , 6.3
so, number of non-zero elements in first row =5
now, we can add them
so,
total number of non-zero elements = 4 +3+3+4+5
so,
total number of non-zero elements is 19...........Answer
Let's say
a = 215,658
ok... so.. he first lost 1/3 of that

so, his nickname might just be even steven, because, he ended up with the same original amount after the 1/2 bump.
Answer:
Cost of travel insurance for 4 days = 19 pounds
Step-by-step explanation:
The insurance company uses the formula T = 3.5n + 5 to work out the cost , T pounds for insuring the customer for n number of days . Where n is the number of days.
The algebraic equation given has two variables which are cost T of insuring and n which is the number of days for insuring. Mathematically,
T = cost of insuring in pounds
n = number of days
Therefore, finding the cost T for 4 days
T = 3.5n + 5
T = 3.5 × 4 + 5
T = 14 + 5
T = 19 pounds
Cost of travel insurance for 4 days = 19 pounds
Starting from what I know (the difference between ribbons), I decided to go from the bottom and work my way up. I then noticed a pattern (each sum was three more of the previous one), and decided to keep my pattern of the three numbers but not have to do any major mental work and instead add three to the previous sum until I got to 38.