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Lina20 [59]
2 years ago
8

Ill give a tip

Mathematics
1 answer:
e-lub [12.9K]2 years ago
7 0
Divide the APR by 360 days and multiply it by 30 days to get the monthly interest. Each loan is usually secured by the car you bought. So we will use the secured APR.

8. Average rating secured apr: 5.85% divide by 360 multiply by 30:  0.4875% monthly rate
Cost of car: 19,725 ; sales tax: 4.75% ; down payment: 2,175

19,725 x 1.0475 =  20,661.94 - 2,175 = 18,486.94 loan amount
18,486.94 x 0.4875% = 90.12 accrued interest for the 1st month.

9. Excellent rating secured apr: 4.80% divide by 360 multiply by 30: 0.40% monthly rate
Cost of car: 15,867 ; sales tax: 5.25% ; down payment: 10% of total cost

15,867 x 1.0525 =  16,700.02 x 90% = 15,030.02 the principal balance at the start of the loan.

10. Fair rating secured apr: 7% divide by 360 multiply by 30: 0.5833% monthly rate
Cost of new car: 19,072 ; sales tax: 4.5% ; down payment: 1,200
Cost of used car: 15,365; sales tax: 4.5% ; down payment: 1,200

19,072 x 1.045 = 19,930.24 - 1,200 = 18,730.24
18,730.24 x 0.5833% = 109.25 accrued interest

15,365 x 1.045 = 16,056.43 - 1,200 = 14,856.43
14,856.43 x 0.5833% = 86.66 accrued interest

109.25 - 86.66 = 22.59 is the difference in interest accrued by the end of the first month.
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Which angles form a linear pair? AnglePRL and AngleLRM AngleORP and AngleMRN AngleMRN and AngleNRO AngleLRP and AngleORP
Andrew [12]

Answer: C (AngleMRN and AngleNRO)

Step-by-step explanation:

A linear pair of angles is formed when two lines intersect. Two angles are linear if they are adjacent angles (angles next to each other) formed by two intersecting lines. The measure of a straight angle is 180 degrees, so a linear pair of angles must add up to 180 degrees.

AngleMRN and AngleNRO together is 180 degrees

I'm not very good at explaining but hope this helps ! :)

4 0
2 years ago
Which of the following best defines 3 to the power of 2 over 3?
Hatshy [7]
If the question is 3^(2/3), The answer is the cube root of 9.
4 0
2 years ago
Read 2 more answers
In the diagram, AB and EF are horizontal lines and CB is a vertical line segment. If FB : FC = 4 : 3, what are the coordinates o
sergij07 [2.7K]
For the answer to the question above, are your diagram shows that the horizontal lines and is a vertical line segment where as FB: 3 , If C is equaled to 3, so the coordinate of the point D would be (-6,-4).I hope my answer helped you.
8 0
2 years ago
Read 2 more answers
Carolina is mowing lawns for a summer job. For every mowing job, she charges an initial fee plus \$6$6dollar sign, 6 for each ho
Margarita [4]

For this case, the first thing we must do is define variables.

We have then:

t: number of hours

F (t): total charge

We write the function that models the problem:

F (t) = 6t + b

Where,

b: represents an initial fee.

We must find the value of b.

For this, we use the following data:

Her total fee for a 4-hour job, for instance, is $ 32.

We have then:

32 = 6 (4) + b

From here, we clear the value of b:

32 = 24 + b

32-24 = b

b = 8

Then, the function that models the problem is:

F (t) = 6t + 8

Answer:

the function's formula is:

F (t) = 6t + 8

7 0
2 years ago
Assume that x and y are both differentiable functions of t and find the required values of dy/dt and dx/dt. x2 + y2 = 25 (a) Fin
Artemon [7]

Answer:

(a) \frac{dy}{dt}=-3\frac{3}{4}

(b) \frac{dx}{dt}=3\frac{3}{4}

Step-by-step explanation:

x^{2} +y^{2}=25

Take \frac{d}{dt} of of each term.

\frac{d}{dt}(x^{2})+\frac{d}{dt}(y^{2})=\frac{d}{dt}(25)\\\\(\frac{d}{dx}(x^{2})*\frac{dx}{dt}) +(\frac{d}{dy}(y^{2})*\frac{dy}{dt})=\frac{d}{dt}(25)\\\\2x\frac{dx}{dt} +2y\frac{dy}{dt} = 0\\\\

For Question a

2y\frac{dy}{dt}=-2x\frac{dx}{dt}\\\\\frac{dy}{dt}=\frac{-2x\frac{dx}{dt}}{2y} \\\\\frac{dy}{dt}=-\frac{x}{y}\frac{dx}{dt}

Given that x = 3, y = 4, and dx/dt = 5.

\frac{dy}{dt}=-\frac{3}{4}*5=-\frac{15}{4}\\   \\\frac{dy}{dt}=-3\frac{3}{4}

For Question b

2x\frac{dx}{dt}=-2y\frac{dy}{dt}\\\\\frac{dx}{dt}=\frac{-2y\frac{dy}{dt}}{2x} \\\\\frac{dx}{dt}=-\frac{y}{x}\frac{dy}{dt}

Given that x = 4, y = 3, and dx/dt = -5.

\frac{dx}{dt}=-\frac{3}{4}*-5=\frac{15}{4}\\   \\\frac{dx}{dt}=3\frac{3}{4}

5 0
2 years ago
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