Break even is the value of t where revenue=cost or R(t)=C(t)
set equal each other
-50t^2+300t=600-50t
multiply both sides by -1
50t^2-300t=50t-600
divide both sides by 50
t^2-6t=t-12
minus t-12 from both sides
t^2-7t+12=0
factor
(t-4)(t-3)=0
set each to zero
t-4=0
t=4
t-3=0
t=3
the cost is $3 or $4
it will first break even at t=3$
I think Mr. Han is around the 60 or 70 age.
I am really sorry that I couldn't answer this problem. Try starting with 21 and multiply that by 3. To check if you can do it, add 43 to the number you multiply 3 with. Again, i am really sorry that i only wrote a hint. Good luck finding the answer!
I'm not sure what your book is saying about the matter but a cell phone is not usually an essential expense. If it is saying it is though, it would be an essential flexible expense.
We can use t=x^2 to solve this
Once we do that we will have simple square equation which we know how to solve.
t^2 + 3t + 2 = 0
t1 = -1
t2 = -2
x1 = √-1 = i
x2 = -i
x3 = √-2 = i√2
x4 = -i√2
Make sure you know that i^2 = -1 and (-i)^2 = -1 which gives us solutions we got...
No, Leo's answer is not a product of prime polynomials because x2 – 1 can be factored. This is a difference of squares. He should continue factoring to get
(x – 1)(x + 1)(3x + 5).
