The diagram shows a rhombus inside a regular hexagon work out the angle x
1 answer:
Answer:
<u>x = 60°</u>
Step-by-step explanation:
The rest of the question is the attached figure.
Given: A rhombus inside a regular hexagon, work out the angle x.
As shown
ABCDEF is a regular hexagon.
The regular hexagon have 6 congruent angles, and the sum of the interior angles is 720°
So, the measure of one angle of the regular hexagon = 720/6 = 120°
So, ∠F = ∠BAF = 120°
AFEG is a rhombus.
The rhombus have 2 obtuse angles and 2 acute angles.
∠F is one of the obtuse angles of the rhombus = 120°
∠F and ∠FA G are supplementary angles
So, ∠F + ∠FA G = 180°
∴ ∠FA G = 180° - ∠F = 180 - 120 = 60°
∴ x = ∠GAB = ∠BAF - ∠FA G = 120 - 60 = 60°
<u>So, the measure of the angle x = 60°</u>
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Step-by-step explanation:
Given that the mean incubation time for a type of fertilized egg kept at a certain temperature is 25 days.
Let X be the incubation time for a type of fertilized egg kept at a certain temperature is 25 days.
X is N(25, 1)
a) Normal curve is in the attached file
b) the probability that a randomly selected fertilized egg hatches in less than 23 days
=
we convert x into Z score and use std normal distn table to find probability
i.e. we can say only 2.5% proportion will hatch in less than 23 days.
