Answer:
According to the proble, the total number of goals are 1+11+15+23 = 50: 1 by the goalkeeper, 11 by defense, 15 by midfielders and 23 by strikers.
So, each probability can be found by using standard probabilities
Therefore, the defense has a probability of 22% of score that goal.
<h3>(b) Midfielders</h3>Therefore, midfielders have a probability of 30% of scoring that goal.
<h3>(c) Strikers.</h3>Therefore, strikers have a probability of 46% of scoring that goal.
Answer:
The probability of a selection of 50 pages will contain no errors is 0.368
The probability that the selection of the random pages will contain at least two errors is 0.2644
Step-by-step explanation:
From the information given:
Let q represent the no of typographical errors.
Suppose that there are exactly 10 such errors randomly located on a textbook of 500 pages. Let be the random variable that follows a Poisson distribution, then mean
and the mean that the random selection of 50 pages will contain no error is
∴
Pr(q =0) = 0.368
The probability of a selection of 50 pages will contain no errors is 0.368
The probability that 50 randomly page contains at least 2 errors is computed as follows:
P(X ≥ 2) = 1 - P( X < 2)
P(X ≥ 2) = 1 - [ P(X = 0) + P (X =1 )] since it is less than 2
P(X ≥ 2) = 0.2644
The probability that the selection of the random pages will contain at least two errors is 0.2644