Given:
On the first day, she drove 650 miles in 10 hours.
On the second day, she got a later start and drove 540 miles in 8 hours.
To find:
Difference between average speed of second day and first day.
Solution:
We know that,

On the first day, she drove 650 miles in 10 hours. So, the average speed is


So, the average speed on first day is 65 miles per hour.
On the second day, she got a later start and drove 540 miles in 8 hours.


So, the average speed on second day is 67.5 miles per hour.
Difference between average speed is

Therefore, the average speed on the second day is 2.5 miles per hour is faster than first day.
To find 20% of 950 you would set it up as a proportion. When doing percentages the prevent is always out of 100 so the first step would be 20/100. You are trying to find a number out of 950 so the second part would be ?/950. Now you want to cross multiply and divide. 20*950=19,000 then you divide it by 100 (your other number) 19,000/100=190. So 20% of 950 is 190.
Answer:
14t + 58 ≤ 150
Step-by-step explanation:
If she cannot spend more than what she has, which is 150, the inequality sign has to be "less than or equal to". It's ok if she spends less than 150, but not ok if she spends more, because she doesn't have it to spend.
We know the cost of 1 pair of jeans is 58. Now she wants to make up the difference by getting as many $14 shirts as possible (the number of shirts being our unknown).
That means that the cost of the jeans PLUS the unknown number of shirts cannot exceed 150.
Therefore, the inequality is:
14t + 58 ≤ 150
Answer:
(a) PC(C)= 
(b) E[C] = 24 cents
Step-by-step explanation:
Given:
Cost to receive a photo = 20 cents
Cost to send a photo = 30 cents
Probability of receiving a photo = 0.6
Probability of sending a photo = 0.4
We need to find
(a) PC(c)
(b) E[C]
Solution:
(a)
PC(C)= 
(b)
Expected value can be calculated by multiplying probability with cost.
E[C] = Probability × cost
E[C] = 