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sasho [114]
1 year ago
14

5.44 Teaching descriptive statistics: A study compared five different methods for teaching descriptive statistics. The five meth

ods were traditional lecture and discussion, programmed textbook instruction, programmed text with lectures, computer instruction, and computer instruction with lectures. 45 students were randomly assigned, 9 to each method. After completing the course, students took a 1-hour exam. (a) What are the hypotheses for evaluating if the average test scores are different for the different teaching methods?
Mathematics
1 answer:
maria [59]1 year ago
7 0

Answer:

The null hypothesis is that all the different teaching methods have the same average test scores.

H0: μ1 = μ2 = μ3 = μ4 = μ5

The alternative hypothesis is that at least one of the teaching methods have a different mean.

Ha: at least one mean is different. (μ1 ≠ μi)

Step-by-step explanation:

The null hypothesis (H0) tries to show that no significant variation exists between variables or that a single variable is no different than its mean. While an alternative Hypothesis (Ha) attempt to prove that a new theory is true rather than the old one. That a variable is significantly different from the mean.

For the case above, let μ represent the average test scores for the teaching methods:

The null hypothesis is that all the different teaching methods have the same average test scores.

H0: μ1 = μ2 = μ3 = μ4 = μ5

The alternative hypothesis is that at least one of the teaching methods have a different mean.

Ha: at least one mean is different. (μ1 ≠ μi)

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14 inches per minute.
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Greta is taking a road trip from Cincinnati to San Francisco. On the first day, she drove 650 miles in 10 hours. On the second d
abruzzese [7]

Given:

On the first day, she drove 650 miles in 10 hours.

On the second day, she got a later start and drove 540 miles in 8 hours.

To find:

Difference between average speed of second day and first day.

Solution:

We know that,

Speed=\dfrac{Distance}{Time}

On the first day, she drove 650 miles in 10 hours.  So, the average speed is

Speed=\dfrac{650}{10}

Speed=65

So, the average speed on first day is 65 miles per hour.

On the second day, she got a later start and drove 540 miles in 8 hours.

Speed=\dfrac{540}{8}

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So, the average speed on second day is 67.5 miles per hour.

Difference between average speed is

67.5-65=2.5

Therefore, the average speed on the second day is 2.5 miles per hour is faster than first day.

3 0
1 year ago
Which expression shows a way to find 20% of 950?<br> 950<br> 20<br> 20<br> What is it
Komok [63]
To find 20% of 950 you would set it up as a proportion. When doing percentages the prevent is always out of 100 so the first step would be 20/100. You are trying to find a number out of 950 so the second part would be ?/950. Now you want to cross multiply and divide. 20*950=19,000 then you divide it by 100 (your other number) 19,000/100=190. So 20% of 950 is 190.
3 0
1 year ago
Lisa has $150 at most to spend on clothes. She wants to buy a pair of jeans for $58 and will spend the rest on t-shirts that cos
anzhelika [568]

Answer:

14t + 58 ≤ 150

Step-by-step explanation:

If she cannot spend more than what she has, which is 150, the inequality sign has to be "less than or equal to".  It's ok if she spends less than 150, but not ok if she spends more, because she doesn't have it to spend.

We know the cost of 1 pair of jeans is 58.  Now she wants to make up the difference by getting as many $14 shirts as possible (the number of shirts being our unknown).  

That means that the cost of the jeans PLUS the unknown number of shirts cannot exceed 150.

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2 years ago
It costs 20 cents to receive a photo and 30 cents to send a photo from a cellphone. C is the cost of one photo (either sent or r
ddd [48]

Answer:

(a) PC(C)=     \left \{ {{0.6 \ \ \ \ x=20} \atop 0.4 \ \ \ \ {x=30}} \right. \\\ 0 \ \ \ \ \ \ \ else

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Step-by-step explanation:

Given:

Cost to receive a photo = 20 cents

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We need to find

(a) PC(c)

(b) E[C]

Solution:

(a)

PC(C)=     \left \{ {{0.6 \ \ \ \ c=20} \atop 0.4 \ \ \ \ {c=30}} \right. \\\ 0 \ \ \ \ \ \ \ else

(b)

Expected value can be calculated by multiplying probability with cost.

E[C] = Probability × cost

E[C] = 0.6\times20 +0.4 \times 30 = 12 + 12 = 24\  cents

3 0
1 year ago
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