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shusha [124]
2 years ago
10

Graph the line y = kx +1 if it is known that the point M belongs to it: M(1,3)

Mathematics
1 answer:
tigry1 [53]2 years ago
3 0

Answer:

M(x,y) = (1,3) belongs to the line y = 2\cdot x +1. Please see attachment below to know the graph of the line.

Step-by-step explanation:

From Analytical Geometry we know that a line is represented by this formula:

y=k\cdot x + b

Where:

x - Independent variable, dimensionless.

y - Dependent variable, dimensionless.

k - Slope, dimensionless.

b - y-Intercept, dimensionless.

If we know that b = 1, x = 1 and y = 3, then we clear slope and solve the resulting expression:

k = \frac{y-b}{x}

k = \frac{3-1}{1}

k = 2

Then, we conclude that point M(x,y) = (1,3) belongs to the line y = 2\cdot x +1, whose graph is presented below.

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Doug purchased land for $8,000 in 1995. The year value of the land depreciated by 4% each year thereafter. Use an exponential fu
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Step-by-step explanation:

we know that

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2 years ago
A piece of paper is to display ~128~ 128 space, 128, space square inches of text. If there are to be one-inch margins on both si
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Answer:

The dimensions of the smallest piece that can be used are: 10 by 20 and the area is 200 square inches

Step-by-step explanation:

We have that:

Area = 128

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Area = x * y

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x = \frac{128}{y}

When 1 inch margin is at top and bottom

The length becomes:

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When 2 inch margin is at both sides

The width becomes:

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The New Area (A) is then calculated as:

A = (x + 2) * (y + 4)

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A = (\frac{128}{y} + 2) * (y + 4)

Open Brackets

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A = \frac{512}{y} + 2y + 8+128

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To calculate the smallest possible value of y, we have to apply calculus.

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Divide through by 2

256=y^2

Take square roots of both sides

\sqrt{256=y^2

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x = \frac{128}{y}

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Length = x + 2

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To double-check;

Differentiate A'

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A" = \frac{1024}{y^3}

The above value is:

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This means that the calculated values are at minimum.

<em>Hence, the dimensions of the smallest piece that can be used are: 10 by 20 and the area is 200 square inches</em>

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