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Naya [18.7K]
1 year ago
14

Simplify the square root of four over the cubed root of four. four raised to the five sixths power four raised to the one sixth

power four raised to the three halves power four raised to the one third power
Mathematics
1 answer:
romanna [79]1 year ago
7 0

Answer:

(B)4^{1/6}

Four raised to the one-sixth power

Step-by-step explanation:

We want to simplify:  \dfrac{\sqrt{4} }{\sqrt[3]{4} }

First, we apply the fractional law of indices to each term.

\text{If  } a^{1/x}=\sqrt[x]{a},$ then:\\\sqrt{4}=4^{1/2}\\\sqrt[3]{4}=4^{1/3}

We then have:

\dfrac{\sqrt{4} }{\sqrt[3]{4} }=\dfrac{4^{1/2} }{4^{1/3} }\\$Applying the division law of indices: \dfrac{a^m }{a^n }=a^{m-n}\\\dfrac{4^{1/2} }{4^{1/3} }=4^{1/2-1/3}\\\\=4^{1/6}

The correct option is B.

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Patricia can drive 36 kilometers for every 3 liters of gas she puts in her car
Anna35 [415]

Answer:

Patricia will run 132 kilometers with 11 liters of gas.

Step-by-step explanation:

The given table is representing the distance driven by Patricia for every liter of gas she puts in her car.

With 3 liters of gas she drives 36 kilometers.

This means in one liter of gas distance covered by the car = \frac{36}{3}=12 kilometers.

Similarly if the car runs 48 kilometers in 4 liters of gas then per liter distance covered by the gas will be = \frac{48}{4}=12 kilometers

Now with 11 liters of gas distance covered by the car will be = 11×12

= 132 kilometers

Therefore, with 11 liters of gas Patricia can run 132 kilometers.

3 0
1 year ago
Read 2 more answers
Identify the key characteristics of the parent fifth-root function f (x) = ^5sqrtx. Include the following: domain, range, interv
Andre45 [30]

Given functin is :

f\left(x\right)=\sqrt[5]{x}

We know that the domain of the expression is all real numbers except where the expression is undefined. In given function, there is no real number that makes the expression undefined. Hence domain is all real numbers.

Domain: (-∞,∞)

Range is the set of y-values obtained by plugging values from domain so the range will also same.

Range: (-∞,∞)

If we increase value of x then y-value will also increase so that means it is an INCREASING function. You can also verify that from graph.

It crosses x and y-axes both at the origin

Hence x-intercept=0 and y-intercept=0

Graph is not symmetric about y-axis hence it can't be EVEN

Graph is not symmetric about origin so it is ODD.

There is  no breaking point in the graph so that means it is a Continuous function.

There is no hoirzontal or vertical or slant line which seems to be appearing to touch the graph at infinity so there is NO asymptote.

END behaviour means how y-changes when x approaches infinity.

From graph we can see that when x-approaches -∞ then y also approaches ∞.

when x-approaches +∞ then y also approaches +∞.

7 0
2 years ago
The number w and 0.8 are additive inverses.
umka2103 [35]

Since, the number w and 0.8 are additive inverses.

A number 'a' is said to have an additive inverse '-a' if "a+ (-a)= 0".

Since, 'w' and '0.8' are additive inverses of each other such that w + 0.8 = 0

Therefore, the value of 'w' should be '-0.8' so that -0.8 + 0.8 = 0.

So, the value of 'w' is =0.8

Now, Refer to the attached image which represents the position of 0.8 , w ( that is -0.8) and the sum of 0.8 and w.

Sum of 0.8 and w = 0.8 + w

= 0.8 +(-0.8)

= 0.

3 0
1 year ago
Read 2 more answers
An ice cream store has two new flavors: Fantasy and Ecstasy. Each barrel of Fantasy requires 4
Y_Kistochka [10]

Answer:

  • Fantasy: 3 barrels
  • Ecstasy: 1 barrel

Step-by-step explanation:

<u>Given</u>

  Fantasy uses 4 lb of nuts, 3 lb of chocolate, for a profit of $50

  Ecstasy uses 4 lb of nuts, 1 lb of chocolate, for a profit of $40

  In stock are 16 lb of nuts, 10 lb of chocolate

<u>Find</u>

 amount of each to maximize profit

<u>Solution</u>

Let x and y represent barrels of Fantasy and Ecstasy, respectively. Then the limitations on production are ...

  4x +4y ≤ 16 . . . lb of nuts

  3x +y ≤ 10 . . . . lb of chocolate

We want to maximize

  50x +40y

The graph shows the feasible region. Its vertices are ...

  (0, 4), (3, 1), (3.33, 0)

Profit is maximized at $190 when production is 3 barrels of Fantasy and 1 barrel of Ecstasy.

8 0
2 years ago
Management is considering adopting a bonus system to increase production. One suggestion is to pay a bonus on the highest 5 perc
Olegator [25]

Answer:

The bonus will be paid on at least 4099 units.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the percentile of this measure.

In this problem, we have that:

The highest 5 percent is the 95th percentile.

Past records indicate that, on the average, 4,000 units of a small assembly are produced during a week. The distribution of the weekly production is approximately normally distributed with a standard deviation of 60 units. This means that \mu = 4000, \sigma = 60.

If the bonus is paid on the upper 5 percent of production, the bonus will be paid on how many units or more?

The least units that the bonus will be paid is X when Z has a pvalue of 0.95.

Z has a pvalue of 0.95 between 1.64 and 1.65. So we use Z = 1.645

Z = \frac{X - \mu}{\sigma}

1.645 = \frac{X - 4000}{60}

X - 4000 = 60*1.645

X = 4098.7

The number of units is discrete, this means that the bonus will be paid on at least 4099 units.

5 0
2 years ago
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