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Naya [18.7K]
2 years ago
14

Simplify the square root of four over the cubed root of four. four raised to the five sixths power four raised to the one sixth

power four raised to the three halves power four raised to the one third power
Mathematics
1 answer:
romanna [79]2 years ago
7 0

Answer:

(B)4^{1/6}

Four raised to the one-sixth power

Step-by-step explanation:

We want to simplify:  \dfrac{\sqrt{4} }{\sqrt[3]{4} }

First, we apply the fractional law of indices to each term.

\text{If  } a^{1/x}=\sqrt[x]{a},$ then:\\\sqrt{4}=4^{1/2}\\\sqrt[3]{4}=4^{1/3}

We then have:

\dfrac{\sqrt{4} }{\sqrt[3]{4} }=\dfrac{4^{1/2} }{4^{1/3} }\\$Applying the division law of indices: \dfrac{a^m }{a^n }=a^{m-n}\\\dfrac{4^{1/2} }{4^{1/3} }=4^{1/2-1/3}\\\\=4^{1/6}

The correct option is B.

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Josephina is preparing Indian pudding for a party. She is cooking the pudding in a water-tight container submerged in boiling wa
GrogVix [38]

Answer:

a) T(t)= 100e^(-0.0513t)

b) See attachment for graph

y-intercept is inital temperature

domain is t≥0, range is 0 <T≤100

c) 44.9min

Step-by-step explanation:

a) at t=0, T=100

at t=1, T=95

T(t)= Ae^-kt

100=Ae^(-k×0)

A=100

95=100e^(-k

k=0.0513

T(t)= 100e^(-0.0513t)

b) as time reaches infinity, temperature of pudding becomes approximately equal to 0. x-axis is the asyptote of the graph

c) 10= 100e^(-0.0513t)

t= 44.9 min

4 0
2 years ago
Sketch the region enclosed by the given curves. Decide whether to integrate with respect to x or y. Draw a typical approximating
MakcuM [25]

Answer:

A=8.4063u^{2}

Step-by-step explanation:

Be the functions:

y=\frac{3}{x};y=\frac{3}{x^{2}}:x=7

according the graph:

\int\limits^1_7 {\frac{3}{x} } \, dx -\int\limits^1_7 {\frac{3}{x^{2} } } \, dx =3\int\limits^1_7 {\frac{1}{x} } \, dx -3\int\limits^1_7 {\frac{1}{x^{2} } } \, dx=3(\int\limits^1_7 {\frac{1}{x} } \, dx -\int\limits^1_7 {\frac{1}{x^{2} } } \, dx)=3[lnx-\frac{1}{x}](1-7)=3[(ln7-ln1)-(\frac{1}{7}-1)]=3[(1.945-0)-(0.1428-1)]=3*(1.945+0.8571)=3*2.8021=8.4063u^{2}

6 0
2 years ago
5. A grocer wishes to mix two kinds of nuts costing
Alekssandra [29.7K]

Ans:

The solve for x:

2.41x+3.65(248-x)=622.48

2.41x+3.65×248-3.65x=622.48

2.41x-3.65x+905.2=622.48

-1.24x=622.48-905.2

-1.24x= -282.72

x= -282.72÷ -1.24

x=228

Pounds of nuts nper pound $2.41should be included:

228× $2.41

=549.48

Hope it Helps!

8 0
2 years ago
Disney held a breakfast for parents and their children to eat with Mickey mouse. adult tickets cost $17.95 and children's ticket
RUDIKE [14]

Answer:

The number of children attending = 324

The number of adults attending  = 176.

Step-by-step explanation:

Here, the total number of people attending = 500

Let us assume the umber of children attending the breakfast = m

So, the number of adults attending the breakfast = 500 - m

Cost of ticket for each children  = $12.95

So, the cost of m children's tickets = m x ( Cost of 1 children ticket)

=  m x ( $12.95)  = 12.95 m .... (1)

Cost of ticket for each adult  = $17.95

So, the cost of (500 -m)  adults's tickets

= (500 - m) x ( Cost of 1 adult ticket)    = (500 -m) x ( $17.95)  

 = 8,975 - 17.95 m     .... (2)

Now, the total earnings from the total ticket sold = $7355

So, The earning from ( Adult's + children's tickets)  = $7355

⇒  12.95 m  +  8,975 - 17.95 m = $7355

or, - 5 m = 7355 - 8975 =   -1620

or, m = 1620/5 = 324

⇒  m =324

Hence the number of children attending =  m = 324

The number of adults attending = 500 - m = 500 - 324 = 176.

7 0
2 years ago
A square and a rhombus are shown below. Which attribute is true of one of the shapes but not of both
Slav-nsk [51]
The rhombus has 2 obtuse angles, and 2 acute angles. the square has 4 right angles.
4 0
2 years ago
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