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julsineya [31]
1 year ago
13

The number of ducks to geese in Miller's Pond last year was 2:3. This year the ratio of ducks to geese is 5:9. The number of gee

se stayed the same. Did the number of ducks increase or decrease? Explain
Mathematics
1 answer:
My name is Ann [436]1 year ago
4 0
No decreased-

Set up equaivalent ratioo. It started out 2 duck to every 3 geese, continue the pattern and see for a change

ducks   2    4   6
geese   3   6   9

but now its 5 ; 9 instead of 6 to 9, therefore the number of ducks decreased
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Which number line represents the solution to 2.5 – 1.2x < 6.5 – 3.2x? A number line from negative 5 to 5 in increments of 1.
Shkiper50 [21]

Answer:

C. 2 is less than or equal to x

Step-by-step explanation:

E d g e n u i t y 2020

5 0
2 years ago
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A sample of 900 college freshmen were randomly selected for a national survey. Among the survey participants, 372 students were
Rufina [12.5K]

Answer:

a) ME=2.58 \sqrt{\frac{0.413(1-0.413)}{900}}=0.0423

b) 0.413 - 2.58 \sqrt{\frac{0.413(1-0.413)}{900}}=0.371

Step-by-step explanation:

1) Data given and notation  

n=900 represent the random sample taken    

X=372 represent the students were pursuing liberal arts degrees

\hat p=\frac{372}{900}=0.413 estimated proportion of students were pursuing liberal arts degrees

\alpha=0.01 represent the significance level

z would represent the statistic (variable of interest)    

p_v represent the p value (variable of interest)    

p= population proportion of students were pursuing liberal arts degrees

2) Solution to the problem

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 99% confidence interval the value of \alpha=1-0.99=0.01 and \alpha/2=0.005, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=2.58

The margin of error is given by:

ME=z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

If we replace we have:

ME=2.58 \sqrt{\frac{0.413(1-0.413)}{900}}=0.0423

And replacing into the confidence interval formula we got:

0.413 - 2.58 \sqrt{\frac{0.413(1-0.413)}{900}}=0.371

0.413 + 2.58 \sqrt{\frac{0.413(1-0.413)}{900}}=0.455

And the 99% confidence interval would be given (0.371;0.455).

We are confident (99%) that about 37.1% to 45.5% of students were pursuing liberal arts degrees.

7 0
2 years ago
Ava bought some pens for $ 2 each and some pencils for $ 1 each. She bought 3 more pens than pencils and spent a total of $ 12.
Rudiy27

Answer:

Step-by-step explanation:

price of 1 pen= $ 2

price of 1 pencil= $1

total money spent= $12

Let the number of pen be a and number of pencil be b.

 2 a + b = 12   ----------------Equation 1

We have, she bought 3 more pens than pencils

  a - b = 3   ------------------  Equation 2

 Equation 1 +Equation 2,  

   2 a + b +  a - b = 12 + 3

                     3a = 15

                     a = 5

 Substituting in  equation

           5 - b = 3

               b = 2

 Number pencils Ava bought = 2

5 0
2 years ago
Lucy wants to have a fun-filled day without spending too much money. The local zoo charges a $25 entry fee and a parking fee of
ehidna [41]

Answer:

The required system of equations is,

y=25+x

y=20+2x.

Step-by-step explanation:

Let the number of hours spent by Lucy = x

It is given that,

Local zoo charges initial fee $25 and per hour fee $1.

So, the equation representing the cost if Lucy stays 'x' hours is,

y=25+x in dollars.

Also, Local citcus charges initial fee $20 and per hour fee $2.

So, the equation representing the cost if Lucy stays 'x' hours is,

y=20+2x in dollars.

Since, the objective function for the situation is to 'minimize the cost'.

So, upon solving the equations, we will get the minimum value as,

25+x = 20+2x

i.e. x= 5

Thus,

y=25+x implies y=25+5 i.e. y= $30

y=20+2x implies y=20+2\times 5 i.e. y=20+10 i.e. y= $30

Thus, the minimum value is $30.

The required system of equations is,

y=25+x

y=20+2x.

8 0
2 years ago
Marco has drawn a line to represent the perpendicular cross-section of the triangular prism. Is he correct? Explain. triangular
evablogger [386]

Answer:

The correct option is;

Yes, the line should be perpendicular to one of the rectangular faces

Step-by-step explanation:

The given information are;

A triangular prism lying on a rectangular base and a line drawn along the slant height

A perpendicular bisector should therefore be perpendicular with reference to the base of the triangular prism such that the cross section will be congruent to the triangular faces

Therefore Marco is correct and the correct option is yes, the line should be perpendicular to one of the rectangular faces (the face the prism is lying on).

8 0
1 year ago
Read 2 more answers
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