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julsineya [31]
2 years ago
13

The number of ducks to geese in Miller's Pond last year was 2:3. This year the ratio of ducks to geese is 5:9. The number of gee

se stayed the same. Did the number of ducks increase or decrease? Explain
Mathematics
1 answer:
My name is Ann [436]2 years ago
4 0
No decreased-

Set up equaivalent ratioo. It started out 2 duck to every 3 geese, continue the pattern and see for a change

ducks   2    4   6
geese   3   6   9

but now its 5 ; 9 instead of 6 to 9, therefore the number of ducks decreased
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Jerry's Fish Shack claims that 16% of its employees are late to work once a week. The manager surveyed 25 employees and found th
larisa86 [58]

Answer:

We need to conduct a hypothesis in order to test the claim that the true proportion of employess are late to work is 0.16, so we need to apply a one sample proportion test:  

Null hypothesis:p=0.16  

Alternative hypothesis:p \neq 0.16  

z=\frac{0.20 -0.16}{\sqrt{\frac{0.16(1-0.16)}{25}}}=0.546  

p_v =2*P(z>0.546)=0.585  

Step-by-step explanation:

Data given and notation

n=25 represent the random sample taken

\hat p=0.2 estimated proportion  

p_o=0.16 is the value that we want to test

\alpha represent the significance level

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion of employess are late to work is 0.16, so we need to apply a one sample proportion test:  

Null hypothesis:p=0.16  

Alternative hypothesis:p \neq 0.16  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.20 -0.16}{\sqrt{\frac{0.16(1-0.16)}{25}}}=0.546  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:  

p_v =2*P(z>0.546)=0.585  

4 0
2 years ago
Is rap music more popular among young Indians than among young Asians? A sample survey compared 634 randomly chosen Indians aged
BabaBlast [244]

Answer:

Step-by-step explanation:

Confidence interval for the difference in the two proportions is written as

Difference in sample proportions ± margin of error

Sample proportion, p = x/n

Where x = number of successes

n = number of samples

For the indians,

x = 368

n1 = 634

p1 = 368/634 = 0.58

For the asians

x = 130

n2 = 567

p2 = 130/567 = 0.23

Margin of error = z√[p1(1 - p1)/n1 + p2(1 - p2)/n2]

To determine the z score, we subtract the confidence level from 100% to get α

α = 1 - 0.95 = 0.05

α/2 = 0.05/2 = 0.025

This is the area in each tail. Since we want the area in the middle, it becomes

1 - 0.025 = 0.975

The z score corresponding to the area on the z table is 1.96. Thus, confidence level of 95% is 1.96

Margin of error = 1.96 × √[0.58(1 - 0.58)/634 + 0.23(1 - 0.23)/567]

= 1.96 × √0.00038422713 + 0.00031234568)

= 0.052

Confidence interval = 0.58 - 0.23 ± 0.052

Confidence interval = 0.35 ± 0.052

8 0
2 years ago
Two well-known aviation training schools are being compared using random samples of their graduates. It is found that 70 of 140
egoroff_w [7]

Answer:

Step-by-step explanation:

Given that two well-known aviation training schools are being compared using random samples of their graduates

Fly more academy 70 of 140

Blue Yonder   104 of 260

Combined pass = (70+104) out of (140+260)

a) Pooled proportion=\frac{174}{400} \\=0.435

b) H0: p1 = p2

Ha: p1 ≠p2

(two tailed test)

p difference= \frac{70}{140} -\frac{104}{260} =0.10

std error for difference (using pooled proportion) = \sqrt{\frac{0.435*0.565}{400} } \\=0.0248

Test statistic = p difff/std error = 4.034

c) Critical value for 0.05 is 1.96

d) p value is < 0.005

Since p < 0.05 our significant level we reject H0

There is significant difference between the two proportions.

8 0
2 years ago
Mr. Bond's monthly income is Rs. 2400 and his monthly expenditure on rent is Rs.250. The central angle of the sector representin
aniked [119]

Answer:

x = 37.5^{\circ}

Step-by-step explanation:

The central angle of the sector representing rent expenses in the pie chart is found by simple rule of three:

x = \frac{Rs. 250}{Rs. 2400}\times 360^{\circ}

x = 37.5^{\circ}

8 0
2 years ago
The exponential functions y=(1-25)^x-2/5. -10 is shown hraphed along woth the horizontal line y=115 their intersection is (a,115
evablogger [386]

Answer:26

Step-by-step explanation:

Y=1.25^x-2/5-10

Take log of both sides

So Y+10=1.25^x-2/5

So log to base 10 of the two sides of the equation is

Log(Y+10)=X-2/5log1.25.

To make X the subject, divide both sides by log1.25.

Log(Y+10)/log1.25=X-2/5.

Recall that Y was given to be 115

It becomes log(115 +10)/Log1.25=x-0.4

21.64=x-0.4

X=25.6

3 0
2 years ago
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