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Genrish500 [490]
2 years ago
5

A drawer contains black socks and white socks. 80% of the socks are white socks. A number generator simulates randomly selecting

10 socks from the drawer. The number generator is used 10 times and the number of white socks in each trial is shown in the dot plot.
Which description is correct about the number generator being fair or not?

Mathematics
2 answers:
Zielflug [23.3K]2 years ago
5 0

D is the righr Answer

Hope this Helpful:)

Kipish [7]2 years ago
4 0

Answer:

Step-by-step explanation:

80% of the socks are white, and each trial selects 10 socks.  80% of 10 is 8, which is what the number generator picked most of the time.  So it is fair.  The answer is the third option.

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f1(x) = ex, f2(x) = e−x, f3(x) = sinh(x) g(x) = c1f1(x) + c2f2(x) + c3f3(x) Solve for c1, c2, and c3 so that g(x) = 0 on the int
eimsori [14]

Answer:

(C1, C2, C3) = (K, K, -2K)

For K in the interval (-∞, ∞)

Step-by-step explanation:

Given

f1(x) = e^x

f2(x) = e^(-x)

f3(x) = sinh(x)

g(x) = 0

We want to solve for C1, C2 and C3, such that

C1f1(x) + C2f2(x) + C3f3(x) = g(x)

That is

C1e^x + C2e^(-x) + C3sinh(x) = 0

The hyperbolic sine of x, sinh(x), can be written in its exponential form as

sinh(x) = (1/2)(e^x + e^(-x))

So, we can rewrite

C1e^x + C2e^(-x) + C3sinh(x) = 0

as

C1e^x + C2e^(-x) + C3(1/2)(e^x + e^(-x)) = 0

So we have

(C1 + (1/2)C3)e^x + (C2 + (1/2)C3)e^(-x) = 0

We know that

e^x ≠ 0, and e^(-x) ≠ 0

So we must have

(C1 + (1/2)C3) = 0...........................(1)

and

(C2 + (1/2)C3) = 0..........................(2)

From (1)

2C1 + C3 = 0

=> C3 = -2C1.................................(3)

From (2)

2C2 + C3 = 0

=> C3 = -2C2................................(4)

Comparing (3) and (4)

2C1 = 2C2

=> C2 = C1

Let C1 = C2 = K

C3 = -2K

(C1, C2, C3) = (K, K, -2K)

For K in the interval (-∞, ∞)

3 0
2 years ago
Mrs. Dalton needs 1/2 cup mixed nuts for her granola recipe. She only has 1/4 cup measuring cup. Write the amount of mixed nuts
Yuliya22 [10]
Fill up the 1/4 cup measuring cup twice because 2 times 1/4 equals 1/2.
3 0
2 years ago
Read 2 more answers
If a certain number of Grade IV students share 28 or 39 skill books in Mathematics,there are remainders of 4 and 3 books. What i
nadya68 [22]

Answer:

  • 12 students

Step-by-step explanation:

<u>Below numbers are divisible by the number of students:</u>

  • 28 - 4 = 24
  • 39 - 3 = 36

<u>Lets find GCF of 24 and 36:</u>

  • 24 = 2*2*2*3
  • 36 = 2*2*3*3
  • GCF(24,36) = 2*2*3 = 12

The largest possible number of students is 12

7 0
1 year ago
A sequence has a common ratio of Three-halves and f(5) = 81. Which explicit formula represents the sequence? f(x) = 24(Three-hal
Ede4ka [16]

Answer:

f(x)=16\, (\frac{3}{2} )^{x-1}

Step-by-step explanation:

Since we are given the common ratio (3/2), all we need to find to define the geometric sequence, is its multiplicative factor (a) that corresponds to the first term of the sequence - remember that all consecutive terms will be generated by multiplying this first value repeatedly by the common ratio (3/2) as shown below:  

f(1)=a\\f(2)=a\,*\,(\frac{3}{2} )\\f(3)=a\,*\,(\frac{3}{2} )^2\\f(4)=a\,*\,(\frac{3}{2} )^3\\f(5)=a\,*\,(\frac{3}{2} )^4

Since we are given the information that f(5)=81 we can use this to find the value of the first term:

f(5)=\,a\,*\,(\frac{3}{2} )^4\\81=\,a\,*(\frac{81}{16} )\\a\,*\,81=\,81\.*\,16\\a\,=\,16

Notice as well that the first term doesn't contain the common ratio, the second term contains the common ration (3/2) to the power one, the third one contains the common ratio to the power two, the fourth one contains it to the power three, and so forth. So the exponent at which the common ratio appears is always one unit less than the order (x) of the term in question. This concept helps us finalize the expression for the sequence's formula:

f(x)=16\,*\,(\frac{3}{2} )^{x-1}

6 0
2 years ago
Read 2 more answers
The sum of a number b and 3 is greater than 8 and less then 12
snow_lady [41]
The sum of a number b and 3 is greater than 8 and less than 12 <span>=> b + 3 < 8
=> b + 3 > 12

</span> <span>Now, let’s combine this into an expression:
=> 8 < b+3 < 12
=>  (8 - 3) < b < (12 - 3)
=> 5 < b < 9
Thus, the answer in the given situation is 9 because 9 is greater than 8 but less than 12.

</span>



4 0
2 years ago
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